Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 44)
44.
A body of dimensions 1.5 m x 1.0 m x 2 m weighs 3000 kg in water. Its specific gravity is
Discussion:
27 comments Page 2 of 3.
Arya said:
8 years ago
Density = mass/volume.
Density of the body = 3000/(1.5*1*2) = 1000kg/m^3.
Sp.gravity of the body = density of the body/density of water.
Sp.gravity = 1000/1000 = 1.
Density of the body = 3000/(1.5*1*2) = 1000kg/m^3.
Sp.gravity of the body = density of the body/density of water.
Sp.gravity = 1000/1000 = 1.
Ravindra said:
8 years ago
C is the correct option.
Ajay said:
7 years ago
I think it should be 1 because 981Value is not used anywhere.
Pavan said:
7 years ago
1000/981=1.01 not 1.1
So, please correct the answer.
So, please correct the answer.
Viral said:
7 years ago
Weight in air=weight in water + buoyant force.
=3000+(sp gr of water* g * volume displaced).
=3000+(1000*10*3).
=33000 N.
So,
Mass of body=33000/10.
=3300 kg.
Density=3300/3.
=1100.
Sp gr.=1100/1000.
=1.1.
=3000+(sp gr of water* g * volume displaced).
=3000+(1000*10*3).
=33000 N.
So,
Mass of body=33000/10.
=3300 kg.
Density=3300/3.
=1100.
Sp gr.=1100/1000.
=1.1.
(1)
Myank said:
7 years ago
I think if the weight is in kg then G=2.0 but it is in N then G=1.1.
(1)
Sadulla said:
7 years ago
1.0 is the correct answer.
Abhik said:
6 years ago
It should be 1.01.
Abhik said:
6 years ago
The Density of object is mass/volume not weight/volume.
IndicaKing said:
6 years ago
Right. @Amit.
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