Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 44)
44.
A body of dimensions 1.5 m x 1.0 m x 2 m weighs 3000 kg in water. Its specific gravity is
Discussion:
27 comments Page 1 of 3.
Mahesh Bansode said:
2 years ago
The Specific gravity must be 2.
Bikram said:
2 years ago
1.0 is the correct answer.
The specific weight of fluid /specific weight of water =specific gravity.
Therefore,
The Specific weight of fluid=ρ*g.
10* (3000/1. 5*1*2) =10000.
Specific gravity=10000/10*1000=1.
The specific weight of fluid /specific weight of water =specific gravity.
Therefore,
The Specific weight of fluid=ρ*g.
10* (3000/1. 5*1*2) =10000.
Specific gravity=10000/10*1000=1.
(2)
Ifrah said:
3 years ago
Yes, you are right @iralHere weight in water is not 3000kg but 3000N. In this way, the answer will be 1.1
(2)
Bhuvnesh said:
3 years ago
Here, 1 is the correct answer.
MJM Gcek said:
4 years ago
The Answer should be only 1.
ShreyaGiha said:
5 years ago
Weight in water = Weight in air - Buoyant force.
=>3000 = W- 1000*(1.5*1*2) = W-3000.
=>W = 6000kg.
Specific Gravity = 6000/1000*(1.5*1*2) = 2.
Weights should be expressed in N and mass in kg. As in the question, weight is expressed as kg, I have also taken it in kg. Even if it is converted to 'N', the answer would be the same 2. because g will be cancelled in both the cases
=>3000 = W- 1000*(1.5*1*2) = W-3000.
=>W = 6000kg.
Specific Gravity = 6000/1000*(1.5*1*2) = 2.
Weights should be expressed in N and mass in kg. As in the question, weight is expressed as kg, I have also taken it in kg. Even if it is converted to 'N', the answer would be the same 2. because g will be cancelled in both the cases
(6)
ANKIT RAJ said:
6 years ago
Thanks all for explaining it.
IndicaKing said:
6 years ago
Right. @Amit.
Abhik said:
6 years ago
The Density of object is mass/volume not weight/volume.
Abhik said:
6 years ago
It should be 1.01.
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