Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 2 (Q.No. 46)
46.
A cylinder 3 m in diameter and 4 m long retains water one side as shown in the below figure. If the weight of the cylinder is 2000 kgf, the vertical reaction at A is
Discussion:
13 comments Page 1 of 2.
Nushi said:
7 years ago
Vertical reaction = wt Of cylinder - vertical Force.
Vertical force= specific weight * volume,
= 1000 * &pie; *1.5^2 * 4/2.
= 14137 kgf.
Ra= 20000-14137 = 5863 kgf.
Vertical force= specific weight * volume,
= 1000 * &pie; *1.5^2 * 4/2.
= 14137 kgf.
Ra= 20000-14137 = 5863 kgf.
(2)
Rakesh roushan said:
3 years ago
Thank you for explaining @Nushi.
(1)
Shailendra kumar said:
9 years ago
Option A is correct.
Fy = 1000 * 9.81 * ( 3.14 * 1.5^2 * 4/2) = 138685.60 N.
138685.60 ÷ 9.81 = 14137.16 kgf.
Fy = 1000 * 9.81 * ( 3.14 * 1.5^2 * 4/2) = 138685.60 N.
138685.60 ÷ 9.81 = 14137.16 kgf.
Basnet said:
9 years ago
(3.14 * 3^2 * 0.25 * 4 * 2000 + 1000 * 3)/9.81 = 6070.2.
SAMYNATHAN said:
8 years ago
Anyone explain the solution.
Baleno said:
8 years ago
The correct answer should be 12137. 1669 Newton this reaction is acting downward because the upward forces more than downward.
Deepak said:
8 years ago
Cylinder weight will be 20000kgf.
Anshu said:
7 years ago
Please explain me to get the answer.
Kumar Adarsh said:
7 years ago
Yes, right @Baleno.
Basavaraj said:
7 years ago
F(verticle) = 3.142 * R^2 * L * 9.81.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers