Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 2 (Q.No. 46)
46.
A cylinder 3 m in diameter and 4 m long retains water one side as shown in the below figure. If the weight of the cylinder is 2000 kgf, the vertical reaction at A is
Discussion:
13 comments Page 2 of 2.
Nungshi Jr said:
7 years ago
Reaction at B = horizontal force (Fh).
Fh= specific wt * area * y.
= 1000 * 3 * 4 * 3/2,
= 18000 kgf.
Fh= specific wt * area * y.
= 1000 * 3 * 4 * 3/2,
= 18000 kgf.
Aadil bhat said:
4 years ago
@Nungshi Jr.
Yes, you are right. Thanks.
Yes, you are right. Thanks.
JENISH POUDEL said:
2 years ago
Reaction = vertical force by water on A+2000kg
Vertical force = wt of water in a volume[volume here is vertically upward projected portion of water without the semicylindrical portion]
Vertical force = 1000 * vol = 1000 * [3 * 1.4 * 4 - 0.5 * 3.14 * 3^(2) * 4/4 = 1000 * [18 - 14.137].
= 3863kg force.
Then the reaction = 3863 + 2000 = 5863kg.
Vertical force = wt of water in a volume[volume here is vertically upward projected portion of water without the semicylindrical portion]
Vertical force = 1000 * vol = 1000 * [3 * 1.4 * 4 - 0.5 * 3.14 * 3^(2) * 4/4 = 1000 * [18 - 14.137].
= 3863kg force.
Then the reaction = 3863 + 2000 = 5863kg.
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