Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 2 (Q.No. 46)
46.
A cylinder 3 m in diameter and 4 m long retains water one side as shown in the below figure. If the weight of the cylinder is 2000 kgf, the vertical reaction at A is
Discussion:
13 comments Page 1 of 2.
JENISH POUDEL said:
1 month ago
Reaction = vertical force by water on A+2000kg
Vertical force = wt of water in a volume[volume here is vertically upward projected portion of water without the semicylindrical portion]
Vertical force = 1000 * vol = 1000 * [3 * 1.4 * 4 - 0.5 * 3.14 * 3^(2) * 4/4 = 1000 * [18 - 14.137].
= 3863kg force.
Then the reaction = 3863 + 2000 = 5863kg.
Vertical force = wt of water in a volume[volume here is vertically upward projected portion of water without the semicylindrical portion]
Vertical force = 1000 * vol = 1000 * [3 * 1.4 * 4 - 0.5 * 3.14 * 3^(2) * 4/4 = 1000 * [18 - 14.137].
= 3863kg force.
Then the reaction = 3863 + 2000 = 5863kg.
Rakesh roushan said:
2 years ago
Thank you for explaining @Nushi.
Aadil bhat said:
3 years ago
@Nungshi Jr.
Yes, you are right. Thanks.
Yes, you are right. Thanks.
Nushi said:
5 years ago
Vertical reaction = wt Of cylinder - vertical Force.
Vertical force= specific weight * volume,
= 1000 * &pie; *1.5^2 * 4/2.
= 14137 kgf.
Ra= 20000-14137 = 5863 kgf.
Vertical force= specific weight * volume,
= 1000 * &pie; *1.5^2 * 4/2.
= 14137 kgf.
Ra= 20000-14137 = 5863 kgf.
(2)
Nungshi Jr said:
5 years ago
Reaction at B = horizontal force (Fh).
Fh= specific wt * area * y.
= 1000 * 3 * 4 * 3/2,
= 18000 kgf.
Fh= specific wt * area * y.
= 1000 * 3 * 4 * 3/2,
= 18000 kgf.
Basavaraj said:
5 years ago
F(verticle) = 3.142 * R^2 * L * 9.81.
Kumar Adarsh said:
5 years ago
Yes, right @Baleno.
Anshu said:
5 years ago
Please explain me to get the answer.
Deepak said:
6 years ago
Cylinder weight will be 20000kgf.
Baleno said:
6 years ago
The correct answer should be 12137. 1669 Newton this reaction is acting downward because the upward forces more than downward.
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