Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 31)
31.
If H is the depth of water retained by a vertical wall, the height of centre of pressure above the bottom is
Discussion:
35 comments Page 3 of 4.
Hemant kumar said:
6 years ago
Answer is H/3.
Rahul said:
6 years ago
H/2 is correct because when depth is very high or not given then the centre of pressure is acting on the centre of gravity.
Sandeep said:
6 years ago
Both A and B are correct.
A is for triangle and B for the rectangle from the bottom.
A is for triangle and B for the rectangle from the bottom.
Harry said:
6 years ago
For vertical wall - from the top - 2h/3 , from bottom - h/3.
For a triangle with the base at free surface - h/2.
For a triangle with the apex at free surface - 3h/4.
For circle touching free surface - 5h/8.
For a triangle with the base at free surface - h/2.
For a triangle with the apex at free surface - 3h/4.
For circle touching free surface - 5h/8.
Pawan pandey said:
5 years ago
H/3 is the correct answer.
Alok said:
5 years ago
H/3 is the correct answer.
(1)
Pinku said:
5 years ago
Apply the law of hydrostatic pressure. The pressure diagram will be traingle in which the hydrostatic force passes through the cg i.e h/3frm bottom.
(2)
Siddhant Ghuge said:
5 years ago
For Trangular H/2.
For Rectangular 2H/3.
For Rectangular 2H/3.
(1)
Viney bhatia batala said:
5 years ago
Centre of pressure h/2.
Centre of gravity h/3.
Centre of gravity h/3.
(1)
Rohitash Kumar said:
4 years ago
We know that h = x + Ig/Ax.
h = H/3+BH * 3/36/BH/2H/3.
h = H/3+H/6,
h = H/2.
h = H/3+BH * 3/36/BH/2H/3.
h = H/3+H/6,
h = H/2.
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