Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 31)
31.
If H is the depth of water retained by a vertical wall, the height of centre of pressure above the bottom is
Discussion:
35 comments Page 4 of 4.
MJM Gcek said:
4 years ago
Correct, Thanks @Rohitash.
Abdullah khan said:
4 years ago
H/2 is the correct answer. The question is related to the center of the vertical wall not to center of gravity or point of application.
(2)
Shahrukh said:
3 years ago
H/2 will be centroid and the Center of pressure is always below the CG.
So, H/3 is correct.
So, H/3 is correct.
(1)
Engr khan said:
3 years ago
The correct answer is H/3.
(1)
Hemanth said:
3 years ago
Traingle =H/2.
Rectangular=H/3.
Consider a rectangular plate of width b and height h is immersed in water.
h'= Depth of centre of gravity of rectangular plate from free surface = h/2.
Area = bh Moment of inertia through centre of gravity. IG = bh3/12.
h* = Distance of centre of pressure from the free surface of a liquid =( igsin^2@/ah')+h'
For vertical plane surface: θ = 90°
The distance of the centre of pressure from the base = h - 2h/3 = h/3.
Rectangular=H/3.
Consider a rectangular plate of width b and height h is immersed in water.
h'= Depth of centre of gravity of rectangular plate from free surface = h/2.
Area = bh Moment of inertia through centre of gravity. IG = bh3/12.
h* = Distance of centre of pressure from the free surface of a liquid =( igsin^2@/ah')+h'
For vertical plane surface: θ = 90°
The distance of the centre of pressure from the base = h - 2h/3 = h/3.
(1)
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