Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 31)
31.
If H is the depth of water retained by a vertical wall, the height of centre of pressure above the bottom is
Discussion:
35 comments Page 1 of 4.
Hemanth said:
3 years ago
Traingle =H/2.
Rectangular=H/3.
Consider a rectangular plate of width b and height h is immersed in water.
h'= Depth of centre of gravity of rectangular plate from free surface = h/2.
Area = bh Moment of inertia through centre of gravity. IG = bh3/12.
h* = Distance of centre of pressure from the free surface of a liquid =( igsin^2@/ah')+h'
For vertical plane surface: θ = 90°
The distance of the centre of pressure from the base = h - 2h/3 = h/3.
Rectangular=H/3.
Consider a rectangular plate of width b and height h is immersed in water.
h'= Depth of centre of gravity of rectangular plate from free surface = h/2.
Area = bh Moment of inertia through centre of gravity. IG = bh3/12.
h* = Distance of centre of pressure from the free surface of a liquid =( igsin^2@/ah')+h'
For vertical plane surface: θ = 90°
The distance of the centre of pressure from the base = h - 2h/3 = h/3.
(1)
Engr khan said:
3 years ago
The correct answer is H/3.
(1)
Shahrukh said:
3 years ago
H/2 will be centroid and the Center of pressure is always below the CG.
So, H/3 is correct.
So, H/3 is correct.
(1)
Abdullah khan said:
4 years ago
H/2 is the correct answer. The question is related to the center of the vertical wall not to center of gravity or point of application.
(2)
MJM Gcek said:
4 years ago
Correct, Thanks @Rohitash.
Rohitash Kumar said:
4 years ago
We know that h = x + Ig/Ax.
h = H/3+BH * 3/36/BH/2H/3.
h = H/3+H/6,
h = H/2.
h = H/3+BH * 3/36/BH/2H/3.
h = H/3+H/6,
h = H/2.
Viney bhatia batala said:
5 years ago
Centre of pressure h/2.
Centre of gravity h/3.
Centre of gravity h/3.
(1)
Siddhant Ghuge said:
5 years ago
For Trangular H/2.
For Rectangular 2H/3.
For Rectangular 2H/3.
(1)
Pinku said:
5 years ago
Apply the law of hydrostatic pressure. The pressure diagram will be traingle in which the hydrostatic force passes through the cg i.e h/3frm bottom.
(2)
Alok said:
5 years ago
H/3 is the correct answer.
(1)
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