Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 31)
31.
If H is the depth of water retained by a vertical wall, the height of centre of pressure above the bottom is
Discussion:
35 comments Page 2 of 4.
Sudipta said:
8 years ago
The Answer should be 2H/3. As center of pressure= H/2+{(bH^3/12)÷(bH*H/2)}=2H/3.
Naveen Kallan said:
8 years ago
From the bottom it's H/3.
From the free surface of water it's 2H/3.
From the free surface of water it's 2H/3.
(3)
Nayan said:
8 years ago
It's center of pressure, H/2 to surface and H/2 to bottom.
And centroid is 2H/3 below surface.
And centroid is 2H/3 below surface.
Vimesh said:
8 years ago
Not given that total pressure. Only center of pressure from water. Than h/2 is the right answer.
Abhinay said:
8 years ago
It's 2h/3.
Priya said:
7 years ago
It's h/3.
Ajay said:
7 years ago
Thanks for the better explanation @Akshay.
Suresh said:
7 years ago
From top it should be 2/3h.
From bottom 1/3 h.
From bottom 1/3 h.
Kvl said:
7 years ago
The correct Answer is H/2 because CP is always Bellow the CG.
Muhammad Atiq said:
6 years ago
Pressure of water acts in a triangular manner, so its answer is H/3.
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