Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 11)
11.
Most economical section of a circular channel for maximum discharge
Discussion:
21 comments Page 1 of 3.
Vasu said:
9 years ago
How? Explain.
Danny said:
9 years ago
Q MAX AT0.98 dimeter.
Shakeel said:
9 years ago
Explain it. Please.
Yudi said:
8 years ago
Please anyone explain this question.
Sudipta kumar singha said:
8 years ago
Explain it please.
Karmveer said:
8 years ago
Plese anyone explain this question.
Arvind said:
8 years ago
I think hydraulic depth should be .25d not .286d.
Priya said:
8 years ago
Explain the answer.
ANIMUT ESUALEW said:
8 years ago
I think the most economical section is when descharege is increase and hydraulic radius is increase but wetted peremeter is decrese because hydraulic radius=area /wetted permeter to increase radius we must increase diameter so A, B are corect Q=1/N R^2/3S^1/2.
R =area /peremeter.
R =area /peremeter.
Rohit Attarde said:
7 years ago
A is the correct answer.
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