# Civil Engineering - Hydraulics - Discussion

### Discussion :: Hydraulics - Section 1 (Q.No.11)

11.

Most economical section of a circular channel for maximum discharge

 [A]. depth of water = 0.95 diameter of circular section [B]. hydraulic mean depth = 0.286 diameter of circular section [C]. wetted perimeter = 2.6 diameter of circular section [D]. wetted perimeter = 2.83 depth of water [E]. all the above.

Explanation:

No answer description available for this question.

 Vasu said: (Nov 16, 2016) How? Explain.

 Danny said: (Dec 11, 2016) Q MAX AT0.98 dimeter.

 Shakeel said: (Jan 27, 2017) Explain it. Please.

 Yudi said: (Mar 8, 2017) Please anyone explain this question.

 Sudipta Kumar Singha said: (May 18, 2017) Explain it please.

 Karmveer said: (Aug 15, 2017) Plese anyone explain this question.

 Arvind said: (Nov 17, 2017) I think hydraulic depth should be .25d not .286d.

 Priya said: (Dec 31, 2017) Explain the answer.

 Animut Esualew said: (Feb 14, 2018) I think the most economical section is when descharege is increase and hydraulic radius is increase but wetted peremeter is decrese because hydraulic radius=area /wetted permeter to increase radius we must increase diameter so A, B are corect Q=1/N R^2/3S^1/2. R =area /peremeter.

 Rohit Attarde said: (Mar 8, 2018) A is the correct answer.

 Mayank said: (May 2, 2018) I think the answer is 0.25d, not 0.95.

 Shivakumar said: (Sep 8, 2018) Answer is 0.95.

 Hari said: (Dec 27, 2018) Please explain the answer clear and detail.

 Hemant said: (Oct 25, 2019) A is accurate answer.

 Deepakb said: (Dec 28, 2019) 0.95D is for chezy's constant.

 Vinod said: (May 22, 2020) Yes, the Answer is 0.95d.

 Nikhil Dongre said: (Nov 28, 2020) For circular channel, maximum Discharge = 0.95D. Maximum Velocity= 0.81D.

 Balarabe Musa said: (Dec 3, 2020) Most economical section of a circular channel is when the Depth of flow is 0.94 to 0.95 of its Diameter.