Civil Engineering - Hydraulics - Discussion


Most economical section of a circular channel for maximum discharge

[A]. depth of water = 0.95 diameter of circular section
[B]. hydraulic mean depth = 0.286 diameter of circular section
[C]. wetted perimeter = 2.6 diameter of circular section
[D]. wetted perimeter = 2.83 depth of water
[E]. all the above.

Answer: Option E


No answer description available for this question.

Vasu said: (Nov 16, 2016)  
How? Explain.

Danny said: (Dec 11, 2016)  
Q MAX AT0.98 dimeter.

Shakeel said: (Jan 27, 2017)  
Explain it. Please.

Yudi said: (Mar 8, 2017)  
Please anyone explain this question.

Sudipta Kumar Singha said: (May 18, 2017)  
Explain it please.

Karmveer said: (Aug 15, 2017)  
Plese anyone explain this question.

Arvind said: (Nov 17, 2017)  
I think hydraulic depth should be .25d not .286d.

Priya said: (Dec 31, 2017)  
Explain the answer.

Animut Esualew said: (Feb 14, 2018)  
I think the most economical section is when descharege is increase and hydraulic radius is increase but wetted peremeter is decrese because hydraulic radius=area /wetted permeter to increase radius we must increase diameter so A, B are corect Q=1/N R^2/3S^1/2.
R =area /peremeter.

Rohit Attarde said: (Mar 8, 2018)  
A is the correct answer.

Mayank said: (May 2, 2018)  
I think the answer is 0.25d, not 0.95.

Shivakumar said: (Sep 8, 2018)  
Answer is 0.95.

Hari said: (Dec 27, 2018)  
Please explain the answer clear and detail.

Hemant said: (Oct 25, 2019)  
A is accurate answer.

Deepakb said: (Dec 28, 2019)  
0.95D is for chezy's constant.

Vinod said: (May 22, 2020)  
Yes, the Answer is 0.95d.

Nikhil Dongre said: (Nov 28, 2020)  
For circular channel, maximum Discharge = 0.95D.
Maximum Velocity= 0.81D.

Balarabe Musa said: (Dec 3, 2020)  
Most economical section of a circular channel is when the Depth of flow is 0.94 to 0.95 of its Diameter.

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