Discussion :: Hydraulics - Section 1 (Q.No.11)
|Vasu said: (Nov 16, 2016)|
|Danny said: (Dec 11, 2016)|
|Q MAX AT0.98 dimeter.|
|Shakeel said: (Jan 27, 2017)|
|Explain it. Please.|
|Yudi said: (Mar 8, 2017)|
|Please anyone explain this question.|
|Sudipta Kumar Singha said: (May 18, 2017)|
|Explain it please.|
|Karmveer said: (Aug 15, 2017)|
|Plese anyone explain this question.|
|Arvind said: (Nov 17, 2017)|
|I think hydraulic depth should be .25d not .286d.|
|Priya said: (Dec 31, 2017)|
|Explain the answer.|
|Animut Esualew said: (Feb 14, 2018)|
|I think the most economical section is when descharege is increase and hydraulic radius is increase but wetted peremeter is decrese because hydraulic radius=area /wetted permeter to increase radius we must increase diameter so A, B are corect Q=1/N R^2/3S^1/2.
R =area /peremeter.
|Rohit Attarde said: (Mar 8, 2018)|
|A is the correct answer.|
|Mayank said: (May 2, 2018)|
|I think the answer is 0.25d, not 0.95.|
|Shivakumar said: (Sep 8, 2018)|
|Answer is 0.95.|
|Hari said: (Dec 27, 2018)|
|Please explain the answer clear and detail.|
|Hemant said: (Oct 25, 2019)|
|A is accurate answer.|
|Deepakb said: (Dec 28, 2019)|
|0.95D is for chezy's constant.|
|Vinod said: (May 22, 2020)|
|Yes, the Answer is 0.95d.|
|Nikhil Dongre said: (Nov 28, 2020)|
|For circular channel, maximum Discharge = 0.95D.
Maximum Velocity= 0.81D.
|Balarabe Musa said: (Dec 3, 2020)|
|Most economical section of a circular channel is when the Depth of flow is 0.94 to 0.95 of its Diameter.|
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