Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 43)
43.
The ratio of the hydraulic radius of a pipe running full to the hydraulic radius of a square section of a channel whose side is equal to the diameter of the pipe, is
1
Discussion:
22 comments Page 3 of 3.
Timi said:
2 years ago
@All.
Option A, 1 would be correct if it was a square pipe. Here it is a channel. So three sides would be included in wetted parameters.
Option A, 1 would be correct if it was a square pipe. Here it is a channel. So three sides would be included in wetted parameters.
(1)
Inayat Ullah Kakar said:
11 months ago
It is very simple;
R = D/4 for circular section
And for;
In square section we know that;
R = area/ wetted perimeter
R = BD/B + 2D.
In questions that B= D because of the square section
R = D^2/3D
R =D/3
So, ratio R1/R2.
D/4รท D/3.
We get 3/4.
So the given answer is correct.
R = D/4 for circular section
And for;
In square section we know that;
R = area/ wetted perimeter
R = BD/B + 2D.
In questions that B= D because of the square section
R = D^2/3D
R =D/3
So, ratio R1/R2.
D/4รท D/3.
We get 3/4.
So the given answer is correct.
(3)
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