Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 43)
43.
The ratio of the hydraulic radius of a pipe running full to the hydraulic radius of a square section of a channel whose side is equal to the diameter of the pipe, is
1
Discussion:
22 comments Page 2 of 3.
Archana Shaji said:
7 years ago
Question asked is square channel section.
So the wetted perimeter for square channel section is 3d. Hence hydraulic radius = d^2/3d = d/3.
Hydraulic radius of the circular pipe is d/4. So the correct answer is 3/4.
So the wetted perimeter for square channel section is 3d. Hence hydraulic radius = d^2/3d = d/3.
Hydraulic radius of the circular pipe is d/4. So the correct answer is 3/4.
(1)
Ajith said:
7 years ago
Here it is a square channel, not a square pipe so perimeter is only 3d.
(1)
Jay said:
7 years ago
@All.
But remember the question says that the square section is running full to the wetted perimeter should be 4D and not 3D and by this, the answer should be A.
But remember the question says that the square section is running full to the wetted perimeter should be 4D and not 3D and by this, the answer should be A.
Abhik said:
7 years ago
D is correct, i.e R = A\P.
Hasmukh parmar said:
6 years ago
The hydraulic radius of circle = d/4.
The hydraulic radius of square = d/3 ( because here we are considering wetted perimeter so two sides and bottom are wetted but top width is not wetted because it's open in the atmosphere)
So, correct answer is = d.3/d.4 = 3/4.
The hydraulic radius of square = d/3 ( because here we are considering wetted perimeter so two sides and bottom are wetted but top width is not wetted because it's open in the atmosphere)
So, correct answer is = d.3/d.4 = 3/4.
(2)
Ketema Feye said:
5 years ago
Agree, D is the correct answer.
Dhiru said:
4 years ago
A is the correct option.
So, R = d/4-d/4 = 1.
So, R = d/4-d/4 = 1.
(1)
Saurabh said:
3 years ago
D is the correct answer.
Hydraulic radius of circular section = D/4.
And for square = D/3,
So, the ratio is = 3/4.
Hydraulic radius of circular section = D/4.
And for square = D/3,
So, the ratio is = 3/4.
(4)
Hemanth said:
3 years ago
Answer is 1.
In question, they are asking about hydraulic radius, not hydraulic mean depth Hydraulic radius RC.
The hydraulic diameter of circles D=4A/P RADIUS=D/2
A= √D2/4 P=√D.
For square section side D.
A=D^2 P=4D.
RATIO CIRCLES/SQUARE.
THE ANSWER IS 1.
OPTION A IS CORRECT.
In question, they are asking about hydraulic radius, not hydraulic mean depth Hydraulic radius RC.
The hydraulic diameter of circles D=4A/P RADIUS=D/2
A= √D2/4 P=√D.
For square section side D.
A=D^2 P=4D.
RATIO CIRCLES/SQUARE.
THE ANSWER IS 1.
OPTION A IS CORRECT.
(2)
Jero M said:
3 years ago
According to me, it's option A.
(1)
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