Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 4 (Q.No. 43)
43.
The ratio of the hydraulic radius of a pipe running full to the hydraulic radius of a square section of a channel whose side is equal to the diameter of the pipe, is
1
Discussion:
22 comments Page 1 of 3.
Saurabh said:
3 years ago
D is the correct answer.
Hydraulic radius of circular section = D/4.
And for square = D/3,
So, the ratio is = 3/4.
Hydraulic radius of circular section = D/4.
And for square = D/3,
So, the ratio is = 3/4.
(4)
Inayat Ullah Kakar said:
11 months ago
It is very simple;
R = D/4 for circular section
And for;
In square section we know that;
R = area/ wetted perimeter
R = BD/B + 2D.
In questions that B= D because of the square section
R = D^2/3D
R =D/3
So, ratio R1/R2.
D/4รท D/3.
We get 3/4.
So the given answer is correct.
R = D/4 for circular section
And for;
In square section we know that;
R = area/ wetted perimeter
R = BD/B + 2D.
In questions that B= D because of the square section
R = D^2/3D
R =D/3
So, ratio R1/R2.
D/4รท D/3.
We get 3/4.
So the given answer is correct.
(3)
Hemanth said:
3 years ago
Answer is 1.
In question, they are asking about hydraulic radius, not hydraulic mean depth Hydraulic radius RC.
The hydraulic diameter of circles D=4A/P RADIUS=D/2
A= √D2/4 P=√D.
For square section side D.
A=D^2 P=4D.
RATIO CIRCLES/SQUARE.
THE ANSWER IS 1.
OPTION A IS CORRECT.
In question, they are asking about hydraulic radius, not hydraulic mean depth Hydraulic radius RC.
The hydraulic diameter of circles D=4A/P RADIUS=D/2
A= √D2/4 P=√D.
For square section side D.
A=D^2 P=4D.
RATIO CIRCLES/SQUARE.
THE ANSWER IS 1.
OPTION A IS CORRECT.
(2)
Hasmukh parmar said:
6 years ago
The hydraulic radius of circle = d/4.
The hydraulic radius of square = d/3 ( because here we are considering wetted perimeter so two sides and bottom are wetted but top width is not wetted because it's open in the atmosphere)
So, correct answer is = d.3/d.4 = 3/4.
The hydraulic radius of square = d/3 ( because here we are considering wetted perimeter so two sides and bottom are wetted but top width is not wetted because it's open in the atmosphere)
So, correct answer is = d.3/d.4 = 3/4.
(2)
Ajith said:
7 years ago
Here it is a square channel, not a square pipe so perimeter is only 3d.
(1)
Timi said:
2 years ago
@All.
Option A, 1 would be correct if it was a square pipe. Here it is a channel. So three sides would be included in wetted parameters.
Option A, 1 would be correct if it was a square pipe. Here it is a channel. So three sides would be included in wetted parameters.
(1)
Jero M said:
3 years ago
According to me, it's option A.
(1)
Dhiru said:
4 years ago
A is the correct option.
So, R = d/4-d/4 = 1.
So, R = d/4-d/4 = 1.
(1)
Archana Shaji said:
7 years ago
Question asked is square channel section.
So the wetted perimeter for square channel section is 3d. Hence hydraulic radius = d^2/3d = d/3.
Hydraulic radius of the circular pipe is d/4. So the correct answer is 3/4.
So the wetted perimeter for square channel section is 3d. Hence hydraulic radius = d^2/3d = d/3.
Hydraulic radius of the circular pipe is d/4. So the correct answer is 3/4.
(1)
Suns said:
8 years ago
Hydraulic radius of square is D/3.
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