Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 2 (Q.No. 23)
23.
The absolute minimum sight distance required for stopping a vehicle moving with a speed of 80 km ph, is
Discussion:
15 comments Page 1 of 2.
Dinesh said:
1 decade ago
SSD = lag distance+braking distance.
= v.t + v^2/2gf.
= 22.22*2.5 + (22.2)^2/(2*9.81*0.35).
= 126.5 (near to 120) So answer is (a)120m.
Where v is in m/s and t = reaction time(2.5sec acc. to IRC).
f is longitudinal coefficient of friction.
= v.t + v^2/2gf.
= 22.22*2.5 + (22.2)^2/(2*9.81*0.35).
= 126.5 (near to 120) So answer is (a)120m.
Where v is in m/s and t = reaction time(2.5sec acc. to IRC).
f is longitudinal coefficient of friction.
Sarang mote said:
9 years ago
What is the lag distance?
Jitendra singh said:
9 years ago
Lag distance = vt.
V = m/ s.
T = sec.
V = m/ s.
T = sec.
Salman mohammed said:
9 years ago
SSD = 0.27vt + v.v/254(f +-g/100).
Where t = 2.5.
f = b/n 0.43 and 0.4 interpolate.
So to answer the question in meter we must use this equation.
Where t = 2.5.
f = b/n 0.43 and 0.4 interpolate.
So to answer the question in meter we must use this equation.
Navi said:
9 years ago
Actually its from the direct values given in the books (for 20kmph = 20).
So as (25=25) (30=30) (40=45) (50=60) (60=80) (80=120) & (100=180).
So as (25=25) (30=30) (40=45) (50=60) (60=80) (80=120) & (100=180).
(1)
Ankur said:
9 years ago
How to predict the value of f in such cases?
Asita said:
9 years ago
Yes, right @Navi.
(1)
ANKUR said:
8 years ago
We can predict because we have to calculate min SSD if take f= .15 we get more value but if we take f= .35 we get min value so we take f=.35.
(1)
Pakkirappa said:
8 years ago
V is given in kmph convert to m
I.e 1000/60*60=0.278
Ssd=vt+{v2/2gf}
Where t is time required for understanding the situation this is a constant value.
Ssd=0.27*80*2.5+{(0.27*80)^2/(2*9.81*0.35)}
Ssd=121.6m.
I.e 1000/60*60=0.278
Ssd=vt+{v2/2gf}
Where t is time required for understanding the situation this is a constant value.
Ssd=0.27*80*2.5+{(0.27*80)^2/(2*9.81*0.35)}
Ssd=121.6m.
(4)
Shubham said:
7 years ago
Right @Navi.
(2)
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