Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 2 (Q.No. 23)
23.
The absolute minimum sight distance required for stopping a vehicle moving with a speed of 80 km ph, is
Discussion:
15 comments Page 2 of 2.
Dinesh said:
6 years ago
0.28 * V.t + 0.01V^2/brake efficiency.
V = 80
t = 2.5
And We get exact ans 120.
V = 80
t = 2.5
And We get exact ans 120.
(1)
Lucky Kumar said:
6 years ago
SSD = 0.278Vt+V^2/254(f+S%).
= 0.278*80*2.5+80*80/254(.35).
= 127.6 mtr.
Cofficent of friction (f) = 0.35.
= 0.278*80*2.5+80*80/254(.35).
= 127.6 mtr.
Cofficent of friction (f) = 0.35.
(1)
Mayu said:
5 years ago
Longitudinal friction --------- 0.35 - 0.4.
Lateral friction --------------- 0.15.
Lateral friction --------------- 0.15.
(2)
Dipunku said:
5 years ago
The correct answer is 127.6m.
Ajay Sharma said:
5 years ago
This value is given directly in form of table.
For 80kmph = 120m.
For 80kmph = 120m.
(1)
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