Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 8)
8.
If the ruling gradient on any highway is 3%, the gradient provided on the curve of 300 metre radius, is
Discussion:
63 comments Page 1 of 7.
Jai vislavath said:
7 years ago
As per the IRC recommendations grade compensations should be done only when the Grade is above 4%.
Let's assume now grade compensation required, even though minimum GC of [(30+R)/R] and 75/R should consider. If we use 75/R, we will GC as 0.25 and Using 30+R/R we get 1.1.
So, we should consider only 0.25 instead of 1.1.
Let's assume now grade compensation required, even though minimum GC of [(30+R)/R] and 75/R should consider. If we use 75/R, we will GC as 0.25 and Using 30+R/R we get 1.1.
So, we should consider only 0.25 instead of 1.1.
Tnwalling said:
9 years ago
According to IRC grade compensation is provide if the gradient is steeper than 4% or radius of curvature is less than 305m. Since in the problem radius of curvature is given 300 (<305) we can calculate. The answer is 2.75.
SHUBHAM SINGH said:
3 years ago
The answer should be 3% because it is already flatter than 4%.
As per IRC no GC for less than 4%.
Although as per calculation by formula it is coming out to be 2.75%.
{(30+R)/R OR 75/R}MIN VALUE ADOPTED.
As per IRC no GC for less than 4%.
Although as per calculation by formula it is coming out to be 2.75%.
{(30+R)/R OR 75/R}MIN VALUE ADOPTED.
(12)
Md Afzal Imam said:
2 years ago
If the curve provided is <40 then use the formula 30+R/ 30.
And if curve>40 then use the formula 75/R.
Here we use the latter one;.
Now, 75/300 = 0.25.
Compensated G= 3-0.25 = 2.75.
Answer C is correct.
And if curve>40 then use the formula 75/R.
Here we use the latter one;.
Now, 75/300 = 0.25.
Compensated G= 3-0.25 = 2.75.
Answer C is correct.
(9)
Sabin Acharya said:
8 years ago
As per NRC-2070 grade compensation only required when the gradient of the road is greater than 4% and i.e (30+R)/30, where R is a curve radius in m. And maximum permissible grade compensation is 75/R.
Shahbaz Bashir said:
7 years ago
Although Grade compensation = 30 + R / R = 1.1 and maximum limit of grade compensation = 75/ R = 0.25 but less than 1.1 so,
Compensiated grade = 3% - 0.25% = 2.75% which is less than 4%.
Compensiated grade = 3% - 0.25% = 2.75% which is less than 4%.
Meme said:
4 years ago
If the curve provided is <40 then use the formula 30+R/ 30.
And if curve>40 then use the formula 75/R.
Here we use the latter one;
Now, 75/300 = 0.25.
Compensated G= 3-0.25 = 2.5.
And if curve>40 then use the formula 75/R.
Here we use the latter one;
Now, 75/300 = 0.25.
Compensated G= 3-0.25 = 2.5.
(9)
Meme said:
4 years ago
If the curve provided is <40 then use the formula 30+R/ 30.
And if curve>40 then use the formula 75/R.
Here we use the latter one;
Now, 75/300 = 0.25.
Compensated G= 3-0.25 = 2.5.
And if curve>40 then use the formula 75/R.
Here we use the latter one;
Now, 75/300 = 0.25.
Compensated G= 3-0.25 = 2.5.
(1)
Lone Khursheed said:
8 years ago
According to IRC, the grade compensation is not necessary for gradients flatter than 4% and therefore when applying grade competition correction, the gradients need not be eased beyond 4%.
Vivek kumar gautam said:
1 decade ago
Grade compensation = 30+r/r = 30+300/300 = 330/300 = 1.1,
Ruling gradient = 3%,
Maximum limit of grade compensation = 75/300 = 0.25,
So compensated gradient = 3-0.25 = 2.75.
Ruling gradient = 3%,
Maximum limit of grade compensation = 75/300 = 0.25,
So compensated gradient = 3-0.25 = 2.75.
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