Civil Engineering - GATE Exam Questions - Discussion

Discussion Forum : GATE Exam Questions - Section 4 (Q.No. 33)
33.
The dimensions for the flexural rigidity of a beam element in mass (M), length (L) and time (T) is given by
MT-2
ML3T-2
ML-1T-2
M-1T2
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
14 comments Page 1 of 2.

Nabam nikam said:   3 years ago
My answer is option. B i,e ML^3T^-2.
(2)

Nabam nikam said:   3 years ago
I think Option B is the right answer.
(3)

Khan said:   4 years ago
E = N/m^2 & I= m^4.
EI = N-m^2,
N = Kg-m/s^2,
EI = (Kg-m/s^2)*(m^2),
EI = Kg-m^3/s^2= ML^3S^-2.
(1)

Sahil Chavda said:   5 years ago
In a beam, the flexural rigidity (EI) varies along the length as a function of x as shown in the equation:

Where E is the young's modulus (in Pasual, Pa), I is the second moment of area (in m4). Y is the traverse displacement of the beam x and M(x) is the bending moment at x. The SI unit of flexural rigidity is thus Pa. m4 or Nm4.

So, the Dimension is ML3T-2

S K Jha said:   5 years ago
EI = Nm2 = MLT-2 x L2 = ML3T-2.

Phani said:   7 years ago
(Kg-m/s^2)*1/m = kg/s^2 = MT^-2.

Roy said:   8 years ago
B is the right answer.

POOBATHY said:   8 years ago
Options A correct.

Mahadev said:   8 years ago
@Snehal and @Balia is correct.

E=N/m ^2, I=m^4.
N=mass * gravity = Kg * m/sec.
= ML^3/T.

Balia Ucp said:   8 years ago
Here, EI = [ML^3T ^-2].


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