Civil Engineering - GATE Exam Questions - Discussion


The dimensions for the flexural rigidity of a beam element in mass (M), length (L) and time (T) is given by

[A]. MT-2
[B]. ML3T-2
[C]. ML-1T-2
[D]. M-1T2

Answer: Option D


No answer description available for this question.

Madhu C N said: (Nov 6, 2014)  
Actual answer is ml2.

Paras said: (Jul 14, 2016)  
It's option B.

Flexural rigidity is EI having Nm^2 units.

Snehal Wankhede said: (Sep 2, 2016)  
Option B.

Flexural rigidity = EI = Nmm2 = ML3T-2.

Sadashiva said: (Jan 14, 2017)  
EI = ML^-1T^-2xL^4.

Balia Ucp said: (Mar 14, 2017)  
Here, EI = [ML^3T ^-2].

Mahadev said: (Mar 20, 2017)  
@Snehal and @Balia is correct.

E=N/m ^2, I=m^4.
N=mass * gravity = Kg * m/sec.
= ML^3/T.

Poobathy said: (Jun 29, 2017)  
Options A correct.

Roy said: (Sep 27, 2017)  
B is the right answer.

Phani said: (Mar 10, 2018)  
(Kg-m/s^2)*1/m = kg/s^2 = MT^-2.

S K Jha said: (Sep 10, 2020)  
EI = Nm2 = MLT-2 x L2 = ML3T-2.

Sahil Chavda said: (Dec 12, 2020)  
In a beam, the flexural rigidity (EI) varies along the length as a function of x as shown in the equation:

Where E is the young's modulus (in Pasual, Pa), I is the second moment of area (in m4). Y is the traverse displacement of the beam x and M(x) is the bending moment at x. The SI unit of flexural rigidity is thus Pa. m4 or Nm4.

So, the Dimension is ML3T-2

Khan said: (Jul 16, 2021)  
E = N/m^2 & I= m^4.
EI = N-m^2,
N = Kg-m/s^2,
EI = (Kg-m/s^2)*(m^2),
EI = Kg-m^3/s^2= ML^3S^-2.

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