Discussion :: GATE Exam Questions - Section 4 (Q.No.33)
The dimensions for the flexural rigidity of a beam element in mass (M), length (L) and time (T) is given by
Answer: Option D
No answer description available for this question.
|Madhu C N said: (Nov 6, 2014)|
|Actual answer is ml2.|
|Paras said: (Jul 14, 2016)|
|It's option B.
Flexural rigidity is EI having Nm^2 units.
|Snehal Wankhede said: (Sep 2, 2016)|
Flexural rigidity = EI = Nmm2 = ML3T-2.
|Sadashiva said: (Jan 14, 2017)|
|EI = ML^-1T^-2xL^4.|
|Balia Ucp said: (Mar 14, 2017)|
|Here, EI = [ML^3T ^-2].|
|Mahadev said: (Mar 20, 2017)|
|@Snehal and @Balia is correct.
E=N/m ^2, I=m^4.
N=mass * gravity = Kg * m/sec.
|Poobathy said: (Jun 29, 2017)|
|Options A correct.|
|Roy said: (Sep 27, 2017)|
|B is the right answer.|
|Phani said: (Mar 10, 2018)|
|(Kg-m/s^2)*1/m = kg/s^2 = MT^-2.|
|S K Jha said: (Sep 10, 2020)|
|EI = Nm2 = MLT-2 x L2 = ML3T-2.|
|Sahil Chavda said: (Dec 12, 2020)|
|In a beam, the flexural rigidity (EI) varies along the length as a function of x as shown in the equation:
Where E is the young's modulus (in Pasual, Pa), I is the second moment of area (in m4). Y is the traverse displacement of the beam x and M(x) is the bending moment at x. The SI unit of flexural rigidity is thus Pa. m4 or Nm4.
So, the Dimension is ML3T-2
|Khan said: (Jul 16, 2021)|
|E = N/m^2 & I= m^4.
EI = N-m^2,
N = Kg-m/s^2,
EI = (Kg-m/s^2)*(m^2),
EI = Kg-m^3/s^2= ML^3S^-2.
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