Civil Engineering - Estimating and Costing - Discussion
Discussion Forum : Estimating and Costing - Section 2 (Q.No. 1)
1.
For 100 sq. m cement concrete (1 : 2: 4) 4 cm thick floor, the quantity of cement required, is
Discussion:
25 comments Page 2 of 3.
V C SAWATHKAR said:
4 years ago
For 4cm thick flooring constant of rate analysis is 6.6.
6.6/(1+2+4) = 0.94285,
for 2.5cm thick flooring 4.125.
6.6/(1+2+4) = 0.94285,
for 2.5cm thick flooring 4.125.
MJM Gcek said:
4 years ago
The correct answer is 0.88m3.
Muhammad Tariq said:
4 years ago
The correct answer is 94.
Volume of wet concrete in 4cum.
Volume of dry concrete is=4*1.54( constant),
Total v= 6.61.
Quantity of cement = 1/7 * 6.61 = 0.94.
Volume of wet concrete in 4cum.
Volume of dry concrete is=4*1.54( constant),
Total v= 6.61.
Quantity of cement = 1/7 * 6.61 = 0.94.
(1)
Deepankar said:
4 years ago
The given answer is correct.
1st total volume=100 * 0.04 =4 m^3.
The volume is increased by 10% due to uneven surface which gives = 4 * 1.1 = 4.4 m^3.
This volume is further increased by 50% for dry volume calculation = 4.4 * 1.5 = 6.6 m^3.
So total volume = 6.6 m^3.
For cement = (6.6 * 1)/(1+2+4) = 0.9428 m^3.
1st total volume=100 * 0.04 =4 m^3.
The volume is increased by 10% due to uneven surface which gives = 4 * 1.1 = 4.4 m^3.
This volume is further increased by 50% for dry volume calculation = 4.4 * 1.5 = 6.6 m^3.
So total volume = 6.6 m^3.
For cement = (6.6 * 1)/(1+2+4) = 0.9428 m^3.
(5)
Sahla said:
4 years ago
100 * .04=4cu.m of wet concrete.
To produced 1cu.m of concrete 1.54cu.m of dry concrete required.
1.54 * 4 = 6.16cu.m
6.16/1+2+4 = .88 cu.m of cement reqd.
.88 * 1440 (density of cement)=1267.2 kg.
Or,
1267.2/50kg = 25.34=26 bag of cement.
To produced 1cu.m of concrete 1.54cu.m of dry concrete required.
1.54 * 4 = 6.16cu.m
6.16/1+2+4 = .88 cu.m of cement reqd.
.88 * 1440 (density of cement)=1267.2 kg.
Or,
1267.2/50kg = 25.34=26 bag of cement.
Shiva khadka said:
4 years ago
100*0.04=4*1.54=6.16/7=0.88ans.
So, 0.90cum is the right answer.
So, 0.90cum is the right answer.
(4)
Aman said:
4 years ago
The volume of wet concrete = 100*0.04 = 4.
Increased mortar by 65% in dry mortar.
The volume of dry mortar=4+0.65*4=6.6.
Now,
Cement QTY = 6.6/7 = 0.94ans.
Increased mortar by 65% in dry mortar.
The volume of dry mortar=4+0.65*4=6.6.
Now,
Cement QTY = 6.6/7 = 0.94ans.
(7)
Smruti R said:
4 years ago
The volume of concrete= 100 * .04 = 4.
10% increase for the unevenness + 50% increase for dry volume =4*1.1*1.5 = 6.6cum,
Cement=6.6/(1+2+4).
10% increase for the unevenness + 50% increase for dry volume =4*1.1*1.5 = 6.6cum,
Cement=6.6/(1+2+4).
(1)
MILI said:
3 years ago
@Raj.
Very well analysis. Thanks.
Very well analysis. Thanks.
(5)
Sakshi said:
3 years ago
Qc = (1.65 * 100* 0.04)*1/7.
Qc = 0.94m^3.
Qc = 0.94m^3.
(9)
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