Civil Engineering - Estimating and Costing - Discussion

Discussion Forum : Estimating and Costing - Section 1 (Q.No. 3)
3.
A portion of an embankment having a uniform up-gradient 1 in 500 is circular with radius 1000 m of the centre line. It subtends 180° at the centre. If the height of the bank is 1 m at the lower end, and side slopes 2:1, the earth work involved.
26, 000 m3
26, 500 m3
27, 000 m3
27, 500 m3
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
39 comments Page 1 of 4.

Souvik De said:   9 years ago
Volume of truncated cone= 3.14 * h * ((R * R) + (r * r) + [(R * r)) * (1/3)].

= 3.14 * 1 *((1000 * 1000) + (500 * 500) + (1000 * 500)) * (1/3).
= 27500.
(4)

Dorna said:   3 years ago
Assume semi-circle plan, embankment section of a triangle with 1 m ht and 1 m base, so the total length of the embankment is π* 1000m, so final section with triangle ht 6.283 m.

Then solve, you will get the answer.
(3)

Daya said:   4 years ago
I did not get the answer. Please explain me.
(3)

Girin said:   4 years ago
Haw to calculate it?
(3)

Salman said:   8 years ago
3.14 * 1 * ((1000*1000) + (500 * 500) + (1000*500)) * (1/3) = 1831666.666
Not 27500 why?
(2)

Ranjitha said:   9 years ago
For 2:1 slope top radius is 500m, and we have bottom radius is 1000m.

Volume of truncated cone is 3.14*h*((R*R) + (r*r) + (R*r))*(1/3).

= 3.14*1**((1000*1000) + (500*500) + (1000*500))*(1/3).
= 27500.
(2)

Chethan Rathod said:   8 years ago
It only possible h is not 1.5 I guess slope is 2:1, so according to right angle law.

2^2- 1^2 = 1.7 then only possible.
v= 1/3*3.14*h*(r1^2+r1*r2+r2^2).
(1)

Rezzy said:   4 years ago
I can't get the answer please anyone explain in detail.
(1)

Bastengan said:   6 years ago
Can someone clarify the answer with a formula?

Sandip Rasal said:   6 years ago
How to calculate this?

Please explain in detail.


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