Civil Engineering - Estimating and Costing - Discussion

Discussion :: Estimating and Costing - Section 1 (Q.No.3)

3. 

A portion of an embankment having a uniform up-gradient 1 in 500 is circular with radius 1000 m of the centre line. It subtends 180° at the centre. If the height of the bank is 1 m at the lower end, and side slopes 2:1, the earth work involved.

[A]. 26, 000 m3
[B]. 26, 500 m3
[C]. 27, 000 m3
[D]. 27, 500 m3

Answer: Option D

Explanation:

No answer description available for this question.

Jyotitak said: (Aug 11, 2014)  
Please tell me how to calculate this ?

Nila said: (Aug 13, 2014)  
Is there any formula for this to calculate?

Prince said: (Aug 31, 2014)  
Can anybody please tell how it is calculated ?

Ramesh said: (Feb 9, 2015)  
Determined. The area of circle and depth and height multiply them got it means volume.

Ritu said: (Mar 9, 2015)  
It may theta equal length/radius for a curve than length equal radius multiply angle theta than put formula 2.L.D. root of s. Here s equal 2.

Naveen said: (Jul 20, 2015)  
Please tell the formula.

Mayuri said: (Aug 4, 2015)  
How to calculate?

Puspanjali said: (Aug 16, 2015)  
How it is calculated? What is the formula?

Yogita said: (Aug 26, 2015)  
How can I calculate it?

Durga said: (Sep 2, 2015)  
How to calculated this?

Janu Saibabu said: (Sep 7, 2015)  
How can get this answer?

Jagdish said: (Oct 13, 2015)  
How can calculated this?

Ranjitha said: (Apr 21, 2016)  
For 2:1 slope top radius is 500m, and we have bottom radius is 1000m.

Volume of truncated cone is 3.14*h*((R*R) + (r*r) + (R*r))*(1/3).

= 3.14*1**((1000*1000) + (500*500) + (1000*500))*(1/3).
= 27500.

Souvik De said: (Nov 14, 2016)  
Volume of truncated cone= 3.14 * h * ((R * R) + (r * r) + [(R * r)) * (1/3)].

= 3.14 * 1 *((1000 * 1000) + (500 * 500) + (1000 * 500)) * (1/3).
= 27500.

Rajni said: (Jan 11, 2017)  
Please explain the Solution.

Shankar C said: (Feb 10, 2017)  
I tried this by using the truncated cone formula.

But I cannot get answer anyone explain me clearly?

Santi said: (Mar 2, 2017)  
Not understanding, please explain the solution.

Salman said: (Mar 9, 2017)  
3.14 * 1 * ((1000*1000) + (500 * 500) + (1000*500)) * (1/3) = 1831666.666
Not 27500 why?

Momin Ali said: (Apr 7, 2017)  
The formula value is 1831666.666 not 27500.

I agree @Salman.

Engr. Asghar Ali said: (May 22, 2017)  
Following the data are missing of embankments like Length, top width and super elevation.

Nesti said: (Jun 29, 2017)  
Please, explain in detail.

Chethan Rathod said: (Sep 3, 2017)  
It only possible h is not 1.5 I guess slope is 2:1, so according to right angle law.

2^2- 1^2 = 1.7 then only possible.
v= 1/3*3.14*h*(r1^2+r1*r2+r2^2).

B.Somu Suel said: (Nov 17, 2017)  
How to calculate this problem?

Garry said: (Nov 22, 2017)  
Right @Chethan.

Aamir said: (Dec 22, 2017)  
I think width of the embankment is missing in question. I am correct?

Shandelin Priyanka said: (Jul 16, 2018)  
How to calculate this? Please explain the solution.

Pradeep Kumar said: (Aug 17, 2018)  
How to calculate this? please explain.

Sanaya said: (Sep 24, 2018)  
How to calculate this?

Santhosh Kumar said: (Dec 28, 2018)  
If slope 2:3 then what is the answer? Please explain.

Maneesh Yadav said: (Feb 16, 2019)  
No, it is wrong because this formula is used to calculate the volume cut cone where r = upper portion radius and are is the bottom portion radius.

Raj said: (Mar 12, 2019)  
Please tell me, clearly how to calculate that answer.

Sandip Rasal said: (Jun 30, 2019)  
How to calculate this?

Please explain in detail.

Bastengan said: (Jul 23, 2019)  
Can someone clarify the answer with a formula?

Ranjan said: (Jul 28, 2019)  
How to calculate this? Explain in detail.

Salini said: (Dec 6, 2019)  
How to calculate this?

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