Civil Engineering - Estimating and Costing - Discussion

Discussion Forum : Estimating and Costing - Section 1 (Q.No. 3)
3.
A portion of an embankment having a uniform up-gradient 1 in 500 is circular with radius 1000 m of the centre line. It subtends 180° at the centre. If the height of the bank is 1 m at the lower end, and side slopes 2:1, the earth work involved.
26, 000 m3
26, 500 m3
27, 000 m3
27, 500 m3
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
40 comments Page 1 of 4.

Jayastin said:   2 months ago
Since height from the downside is h1 = 1m.
Consider hm = 2,
h2 = 3.

Then proceed with the Simpson's rule = (L/6)(A1 + 4AM + A2).
L = π x R.
L = 3140.

A1 = S.h1^2 = 2(given).1(height from downside) = 2.
A2 = S.h2^2 = 2 * 9 = 18.
AM = S.hm^2 = 2 * 4 = 8.
Inserting in the Simpson;
(3140/6)(2 + (4*8) + 18).
=27213.333.
Approximately 27,500 m^3.
(2)

Dorna said:   4 years ago
Assume semi-circle plan, embankment section of a triangle with 1 m ht and 1 m base, so the total length of the embankment is π* 1000m, so final section with triangle ht 6.283 m.

Then solve, you will get the answer.
(3)

Rezzy said:   4 years ago
I can't get the answer please anyone explain in detail.
(1)

Daya said:   4 years ago
I did not get the answer. Please explain me.
(3)

Girin said:   4 years ago
Haw to calculate it?
(3)

Salini said:   6 years ago
How to calculate this?

Ranjan said:   6 years ago
How to calculate this? Explain in detail.

Bastengan said:   6 years ago
Can someone clarify the answer with a formula?

Sandip Rasal said:   6 years ago
How to calculate this?

Please explain in detail.

Raj said:   6 years ago
Please tell me, clearly how to calculate that answer.


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