### Discussion :: Estimating and Costing - Section 1 (Q.No.3)

Jyotitak said: (Aug 11, 2014) | |

Please tell me how to calculate this ? |

Nila said: (Aug 13, 2014) | |

Is there any formula for this to calculate? |

Prince said: (Aug 31, 2014) | |

Can anybody please tell how it is calculated ? |

Ramesh said: (Feb 9, 2015) | |

Determined. The area of circle and depth and height multiply them got it means volume. |

Ritu said: (Mar 9, 2015) | |

It may theta equal length/radius for a curve than length equal radius multiply angle theta than put formula 2.L.D. root of s. Here s equal 2. |

Naveen said: (Jul 20, 2015) | |

Please tell the formula. |

Mayuri said: (Aug 4, 2015) | |

How to calculate? |

Puspanjali said: (Aug 16, 2015) | |

How it is calculated? What is the formula? |

Yogita said: (Aug 26, 2015) | |

How can I calculate it? |

Durga said: (Sep 2, 2015) | |

How to calculated this? |

Janu Saibabu said: (Sep 7, 2015) | |

How can get this answer? |

Jagdish said: (Oct 13, 2015) | |

How can calculated this? |

Ranjitha said: (Apr 21, 2016) | |

For 2:1 slope top radius is 500m, and we have bottom radius is 1000m. Volume of truncated cone is 3.14*h*((R*R) + (r*r) + (R*r))*(1/3). = 3.14*1**((1000*1000) + (500*500) + (1000*500))*(1/3). = 27500. |

Souvik De said: (Nov 14, 2016) | |

Volume of truncated cone= 3.14 * h * ((R * R) + (r * r) + [(R * r)) * (1/3)]. = 3.14 * 1 *((1000 * 1000) + (500 * 500) + (1000 * 500)) * (1/3). = 27500. |

Rajni said: (Jan 11, 2017) | |

Please explain the Solution. |

Shankar C said: (Feb 10, 2017) | |

I tried this by using the truncated cone formula. But I cannot get answer anyone explain me clearly? |

Santi said: (Mar 2, 2017) | |

Not understanding, please explain the solution. |

Salman said: (Mar 9, 2017) | |

3.14 * 1 * ((1000*1000) + (500 * 500) + (1000*500)) * (1/3) = 1831666.666 Not 27500 why? |

Momin Ali said: (Apr 7, 2017) | |

The formula value is 1831666.666 not 27500. I agree @Salman. |

Engr. Asghar Ali said: (May 22, 2017) | |

Following the data are missing of embankments like Length, top width and super elevation. |

Nesti said: (Jun 29, 2017) | |

Please, explain in detail. |

Chethan Rathod said: (Sep 3, 2017) | |

It only possible h is not 1.5 I guess slope is 2:1, so according to right angle law. 2^2- 1^2 = 1.7 then only possible. v= 1/3*3.14*h*(r1^2+r1*r2+r2^2). |

B.Somu Suel said: (Nov 17, 2017) | |

How to calculate this problem? |

Garry said: (Nov 22, 2017) | |

Right @Chethan. |

Aamir said: (Dec 22, 2017) | |

I think width of the embankment is missing in question. I am correct? |

Shandelin Priyanka said: (Jul 16, 2018) | |

How to calculate this? Please explain the solution. |

Pradeep Kumar said: (Aug 17, 2018) | |

How to calculate this? please explain. |

Sanaya said: (Sep 24, 2018) | |

How to calculate this? |

Santhosh Kumar said: (Dec 28, 2018) | |

If slope 2:3 then what is the answer? Please explain. |

Maneesh Yadav said: (Feb 16, 2019) | |

No, it is wrong because this formula is used to calculate the volume cut cone where r = upper portion radius and are is the bottom portion radius. |

Raj said: (Mar 12, 2019) | |

Please tell me, clearly how to calculate that answer. |

Sandip Rasal said: (Jun 30, 2019) | |

How to calculate this? Please explain in detail. |

Bastengan said: (Jul 23, 2019) | |

Can someone clarify the answer with a formula? |

Ranjan said: (Jul 28, 2019) | |

How to calculate this? Explain in detail. |

Salini said: (Dec 6, 2019) | |

How to calculate this? |

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