Civil Engineering - Estimating and Costing - Discussion
Discussion Forum : Estimating and Costing - Section 1 (Q.No. 2)
2.
The expected out turn of 2.5 cm cement concrete floor per manson per day
Discussion:
48 comments Page 4 of 5.
Bharat said:
1 decade ago
@Jyotitak calculation is 7.5*0.025.
Dev said:
1 decade ago
@Bharat.
What is 0.025 and what is the unit?
What is 0.025 and what is the unit?
Tarun said:
1 decade ago
For 100 sum, no. of Mason is 13 no.
i.e for 13 Mason flooring is 100 square meter.
So for 1 Mason flooring is 100/13 = 7.69 sum.
So option C is the answer.
i.e for 13 Mason flooring is 100 square meter.
So for 1 Mason flooring is 100/13 = 7.69 sum.
So option C is the answer.
M.Areeb said:
1 decade ago
For 100 sum, no. of Mason is 13 no.
i.e for 13 Mason flooring is 100 square meter.
From where you confirm that it is fixed.
i.e for 13 Mason flooring is 100 square meter.
From where you confirm that it is fixed.
Rajashekar said:
1 decade ago
One per person can place the concrete floor per day 1.875 m3.
= 1.875/0.25 = 7.5 M2.
= 1.875/0.25 = 7.5 M2.
Mounika said:
10 years ago
I didn't understand.
Can anyone give a clear answer please?
Can anyone give a clear answer please?
Saro said:
1 decade ago
Please can anyone tell me how it is find out?
D.Prashanth said:
9 years ago
If one mason can do concrete flooring of 1.875 m3 per day.
So, 1.875/.25 = 7.5 square meter is the correct answer.
So, 1.875/.25 = 7.5 square meter is the correct answer.
Paritosh said:
9 years ago
I want to know how I can confirm that 'one mason can do concrete flooring of 1.875 m3 per day?
Pradosh nayak said:
9 years ago
2.5cm means 0.025M = 1.875/.025=75 sqm. How it is 7.5sqm?
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