Civil Engineering - Estimating and Costing - Discussion
Discussion Forum : Estimating and Costing - Section 1 (Q.No. 2)
2.
The expected out turn of 2.5 cm cement concrete floor per manson per day
Discussion:
48 comments Page 3 of 5.
Naresh said:
8 years ago
I am not getting it. Please explain.
Abcd said:
8 years ago
1 : 2 : 4 concrete, 1m3 need Labour constant.
Mixing concrete --------> 3.00 hour/m3.
Lifting and carrying concrete --------> 1.20 hour/m3.
c.compacting concrete --------> 0.80 hour/m3.
d.leveling surface of concrete --------> 0.10 hour/m3.
Total=(3+1.2+0.8+0.1) = 5.
Mixing concrete --------> 3.00 hour/m3.
Lifting and carrying concrete --------> 1.20 hour/m3.
c.compacting concrete --------> 0.80 hour/m3.
d.leveling surface of concrete --------> 0.10 hour/m3.
Total=(3+1.2+0.8+0.1) = 5.
Satya.M said:
8 years ago
.1875/.025 = 7.5.
Sunil Kumar yadav said:
8 years ago
Here, .1875/.025 = 7.5.
Gawand m. said:
8 years ago
I can't understand the basic behind this. Please explain it clearly.
Ankit said:
8 years ago
.1875/.025 = 7.5sqm.
Erarush said:
9 years ago
It's not depend on this specific values, It only depends on mason efficiency I see masons which cover 10 cum or even more than this of concrete flow.
Prabagaran said:
9 years ago
It is an approximate method. It varies from city to city. A mason is completing 7.5sq m for cement concrete floor per day.
Niketan said:
9 years ago
How it come? Please explain in simple way.
Kesavan V said:
9 years ago
How come this answer?
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