Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 5 (Q.No. 29)
29.
For a concrete mix 1:3:6 and water cement ratio 0.6 both by weight, the quantity of water required per bag, is
10 kg
12 kg
14 kg
16 kg
20 kg
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
57 comments Page 5 of 6.

Mehebub said:   9 years ago
@Salman.

But here told ratio 1:3:6,

Where, 1=Cement, 3=Sand, and 6=Stone.
Therefore Sand + Stone = Aggregate.
So, sum total 3 + 6 = 9. [50x9 = 450Kg].

ARNAB ADAK said:   9 years ago
For ratio, 1:3:6 w/c ratio-0.60.
So water required for 1 bag (50 kg) cement is=50*0.60=30 lit.

Naren said:   9 years ago
Please explain correctly, whether 30 is correct or 14 is correct?

If any then explain how.

Nazim said:   8 years ago
1 bag cement concrete work need for water.

Qasim Ale said:   8 years ago
Excellent explanation. Thank you all.

Nilesh said:   8 years ago
W/c ratio means the ratio of the weight of water to the weight of cement so that 0.6 * 50 = 30 kits or kg.

Kayathri said:   9 years ago
Why we are taking 5% of aggregate and 30% of cement?

Saideepak Nagajjanavar Hangal said:   8 years ago
Let's discuss with the calculation of material for 1cum concrete (1:2:4).

Dry volume m = 1X1.45 (45 % to 55 % Increase in volume = 1.45 cum.
Cement = 1.45/(1+2+4) = 0.207 cumX1470 = 304.29 kg. (Density 1470)
Sand = 1.45/(1+2+4) X2 = 0.414 cum/X1350(Density) = 558.9 Kg.
CA = 0.207X4 = 0.828cumX1300 = 1076.4 Kg.

Therefore 1 : 2 : 4.
304.29 Kg : 558.9 Kg : 1076.4 Kg for 1 CUM.

Sanju said:   8 years ago
Water cement ratio 0.6 means, 50 * 0.6 = 25.

RG Ranjan said:   8 years ago
I think the correct answer is 30 kg.


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