Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 5 (Q.No. 29)
29.
For a concrete mix 1:3:6 and water cement ratio 0.6 both by weight, the quantity of water required per bag, is
Discussion:
57 comments Page 6 of 6.
AMIT ANAND said:
8 years ago
Here we have to know only about the requirement of water for 1-bag of cement.
We know 1bag contain 50 kg cement.
As per w/c ratio its value 0.6 i.e 60 litre pe 100kg cement,
So the density of cement nearly 1440kg/cum,
Density = mass/volume.
So, volume=[mass]/density * 1000,
i.e 50/1440 * 1000,
Ans is 34.7222 which is nearly 35.
Hence 35 kg answer is right.
We know 1bag contain 50 kg cement.
As per w/c ratio its value 0.6 i.e 60 litre pe 100kg cement,
So the density of cement nearly 1440kg/cum,
Density = mass/volume.
So, volume=[mass]/density * 1000,
i.e 50/1440 * 1000,
Ans is 34.7222 which is nearly 35.
Hence 35 kg answer is right.
Vinay said:
8 years ago
For 1:3:6 mix for 1 cu.m.
Total dry volume = 1.5.
Now total cement required is,
--- 1/(1+3+6)*1.5 = 0.15 volume of cement.
= 0.15/0.0347 = 4.33 bags.
1bag- 50kgs,
50*4.333=216 kg,
Approximate 4 bags,
W/c=0.6.
W = 0.6 *200= 120kg.
Water required is 120kg for 4 bag of cement.
For one bag = 120/4 = 30 KGS.
Total dry volume = 1.5.
Now total cement required is,
--- 1/(1+3+6)*1.5 = 0.15 volume of cement.
= 0.15/0.0347 = 4.33 bags.
1bag- 50kgs,
50*4.333=216 kg,
Approximate 4 bags,
W/c=0.6.
W = 0.6 *200= 120kg.
Water required is 120kg for 4 bag of cement.
For one bag = 120/4 = 30 KGS.
Inayat said:
8 years ago
Thanks to all. It was very helpful.
Chijioke said:
8 years ago
Determine the quantities of water needed to mix 150kg of cement used for concrete mix.
Wasim Shaikh said:
8 years ago
Well, the correct answer is 35kg.
Wasim shaikh said:
8 years ago
The density of cement is 1440kg per 1000L(volume).
we know 1 bag of cement = 50 kg.
so how much volume(L) it will require (50x1000) ÷ (1440) =34.722.
which is approximately 35 kg.
But if we use w/c ratio= 0.60 =(wt of water) ÷ (wt of cement)
Then wt of water=.6 x 50 kg=30 kg.
Can anyone clear this?
we know 1 bag of cement = 50 kg.
so how much volume(L) it will require (50x1000) ÷ (1440) =34.722.
which is approximately 35 kg.
But if we use w/c ratio= 0.60 =(wt of water) ÷ (wt of cement)
Then wt of water=.6 x 50 kg=30 kg.
Can anyone clear this?
Kishanjee Gujarath said:
8 years ago
Very good information for civil Engineers.
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