Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 5 (Q.No. 29)
29.
For a concrete mix 1:3:6 and water cement ratio 0.6 both by weight, the quantity of water required per bag, is
Discussion:
57 comments Page 4 of 6.
Robert said:
10 years ago
How did you rear get them I don't get it?
P.s said:
1 decade ago
See 30%of cement means 0.3*50 kg = 15 kg.
5% of fine aggregate 0.05*150 = 7.5 kg.
0.6*(15+7.5) = 13.5 kg+14 kg.
5% of fine aggregate 0.05*150 = 7.5 kg.
0.6*(15+7.5) = 13.5 kg+14 kg.
Suman said:
1 decade ago
0.6 means 60 liter water per 100 kg cement as 1 bag of cement contains 50 kg of cement.
So 60/2 = 30 liter water required per bag of cement.
So 60/2 = 30 liter water required per bag of cement.
Kavita said:
1 decade ago
Please solve this problem. How this answer comes?
Saideepak nagajjanavar Hangal said:
8 years ago
Generally, water cement ratio is taken in between 0.5-0.6.
@Nazim.
w/c= water/cement
0.5= water/1 bag
0.5= water/50kg
water= 25 litres.
@Nazim.
w/c= water/cement
0.5= water/1 bag
0.5= water/50kg
water= 25 litres.
Ajay Agnihotri said:
9 years ago
However, I believe that the density of cement is 1440 Kg/Cum.
Therefore, the volume of a 50 kg cement bag works out to be [ 50/1440 ]*1000 = 34.722 Liters.
Therefore, the volume of a 50 kg cement bag works out to be [ 50/1440 ]*1000 = 34.722 Liters.
Shubham mehta said:
9 years ago
Yeah, that's the Water is required 60% of the cement means if we are considering the 1 bag of 50kg then for water. It will become (60/100) 50 = 30 litres.
Shivkumar said:
9 years ago
Yeah, I agree with the answer 30.
Rakesh Nhavkar said:
9 years ago
It's Thumb Rules for deciding the quantity of water in concrete:
(i) Weight of water = 28% of the weight of cement + 4% of the weight of total aggregate.
(ii) Weight of water = 30% of the weight of cement + 5% of the weight of total aggregate.
(i) Weight of water = 28% of the weight of cement + 4% of the weight of total aggregate.
(ii) Weight of water = 30% of the weight of cement + 5% of the weight of total aggregate.
Ar. SALMAN AFAQUE said:
9 years ago
1:3:6, so we multiply by 1*50 Kg cement and 3 fine aggregate * 50 kg, so.
We get 150 kg fine aggregate.
We get 150 kg fine aggregate.
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