Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 2 (Q.No. 37)
37.
The internal dimensions of a ware house are 15 m x 5.6 m, and the maximum height of piles is 2.70 m, the maximum number of bags to be stored in two piles, are
Discussion:
45 comments Page 5 of 5.
Ayon Som said:
9 years ago
The answer should be 3600 bags.
Internal dimension of warehouse = 15m x 5.6m
Effective storage floor area which is available:
=> (15m - 300mm - 300mm) x (5.6m - 300 mm - 300 mm) = 14.4m x 5m
(300mm distance should be maintained from each exterior wall)
Therefore, No. of bag in one layer = Available area / Area occupied by one bag:
=> 14.4m x 5m / 0.3 sq.m = 240 bags in one layer
No. of layer of bags = Max. height of pile allowed / Height of one bag:
=> 2.7m / 0.18 m = 15 layers.
Therefore, total no. bags can be stored = Total bag in one layer X Total no. of layers:
=> 240 X 15 = 3600 Bags of cement
Hence, The answer should be 3600 bags.
Internal dimension of warehouse = 15m x 5.6m
Effective storage floor area which is available:
=> (15m - 300mm - 300mm) x (5.6m - 300 mm - 300 mm) = 14.4m x 5m
(300mm distance should be maintained from each exterior wall)
Therefore, No. of bag in one layer = Available area / Area occupied by one bag:
=> 14.4m x 5m / 0.3 sq.m = 240 bags in one layer
No. of layer of bags = Max. height of pile allowed / Height of one bag:
=> 2.7m / 0.18 m = 15 layers.
Therefore, total no. bags can be stored = Total bag in one layer X Total no. of layers:
=> 240 X 15 = 3600 Bags of cement
Hence, The answer should be 3600 bags.
Krishna said:
10 years ago
I don't think all the answers are correct. As per guideline we can stack max of 10 bags vertically and we need to keep 600 mm space away from walls. And also need to keep a distance of 600mm between two rows.
Er. soumya choudhury said:
1 decade ago
But volume of one cement bag is 0.035 cum.
Volume of ware house is 15*5.6*2.7 = 226.8 cum.
No of bags = 226.8/0.035 = 6480 bags. In two rows means 3240 bags.
Volume of ware house is 15*5.6*2.7 = 226.8 cum.
No of bags = 226.8/0.035 = 6480 bags. In two rows means 3240 bags.
Prasanta Naskar said:
1 decade ago
We know, surface area and height of pile required for storing of 1 bag of cement are 0.3 sq.m. and 0.18 m respectively.
Therefore, maximum nos of bags can be stored into the given stored house = (15 x 5.6 x 2.7)/(0.3 x 0.18) = 4200.
Therefore, options were wrong.
Therefore, maximum nos of bags can be stored into the given stored house = (15 x 5.6 x 2.7)/(0.3 x 0.18) = 4200.
Therefore, options were wrong.
Sharad said:
1 decade ago
How this answer is possible please explain with size of cement bag or volume of cement bag?
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