Civil Engineering - Concrete Technology - Discussion

Give the explanation of the correct answer, please.

Area-(15-0.3) *(5.6-0.4) =77.91.
1.2m space leaves between two piles 1.2 * 14.7 = 17.69.

Redution 77.91-17.91 = 60.27.
Volume-60. 27 * 2.7 = 162.72 ÷ 054 = 3013.5bag.

Then, what is the answer? Please explain it correctly.

@All.

I don't think the above answers are correct because according to the guidelines for cement warehouses.

1. It is advisable to never stack more than 10 cement bags over each other as this will lead to lumping under pressure.
2. Should provide 600mm space away from the wall.
3. The width of the stack shall not be more than 4 bag width or 3m
4. A passage of 600mm should provide in between each stack for easy access and inspection.

Answer is 4200 bags. It's a perfect answer.

7 bags for 1 cum concrete.

15 * 5.6 * 2.7 = 226.8 cum.
226.8 * 7 = 1587.6 cum for 1 pile.

For 2 piles 2 * 1587.6 = 3175.2 bags.

Length = 15-0.6 = 14.4m.
Breadth=5.6-0.6-0.8=4.2m.
0.8 less for gap b/w two piles.
Area=14.4*4.2=60.48sq.m.
No.of bag in one layer=60.48/0.3=201.6bags.
0.3 area of one bag cement.
2.7/0.18 = 15.
0.18 is the height of one bag cement.
Then, 201.6 * 15=3024 bags -> 3000 bags.

Hi guys, you have a room dimension, but nobody doing deduction properly, between the piles diff should be 1.2 m and 0.30 m from both side wall, but in width. Both side wall deduction. After the deduction, you have the answer, approximately 3600.

Density of cement is 0.035 cum.
And height of pile means the depth of ware house.
Length and breadth of the ware house is given,

For the volume of the ware house (length x breadth x height).
= 15 x 5.6 x 2.7.
= 226.8 cum.

Total quantity of cement = 226.8/0.035.
= 6480cum.
In two row it contains = 3240cum cement total.
So 3000 is suitable option for that because it can contain more than 2000 and less than 4000.

Floor area of the warehouse for 2 number of piles will be:
length = 15 - 0.6 = 14.4.
And breath b = 5.6 - 0.6 - 1 = 4 m.

Because the standard of the gap between two piles is 1 m so area = 14.4 * 4 = 57.6 sqm. And the area of one bag cement 0.3 sqm. So the number of the bag in one layer = 57.6/0.3 = 192 bags and for 2.7 m height mean 15 layers of bags.

So the total number of bags will be 192 * 15 = 2880.