Civil Engineering - Concrete Technology - Discussion

How this answer is possible please explain with size of cement bag or volume of cement bag?

We know, surface area and height of pile required for storing of 1 bag of cement are 0.3 sq.m. and 0.18 m respectively.

Therefore, maximum nos of bags can be stored into the given stored house = (15 x 5.6 x 2.7)/(0.3 x 0.18) = 4200.

Therefore, options were wrong.

But volume of one cement bag is 0.035 cum.

Volume of ware house is 15*5.6*2.7 = 226.8 cum.

No of bags = 226.8/0.035 = 6480 bags. In two rows means 3240 bags.

I don't think all the answers are correct. As per guideline we can stack max of 10 bags vertically and we need to keep 600 mm space away from walls. And also need to keep a distance of 600mm between two rows.

The answer should be 3600 bags.

Internal dimension of warehouse = 15m x 5.6m

Effective storage floor area which is available:
=> (15m - 300mm - 300mm) x (5.6m - 300 mm - 300 mm) = 14.4m x 5m

(300mm distance should be maintained from each exterior wall)

Therefore, No. of bag in one layer = Available area / Area occupied by one bag:
=> 14.4m x 5m / 0.3 sq.m = 240 bags in one layer

No. of layer of bags = Max. height of pile allowed / Height of one bag:
=> 2.7m / 0.18 m = 15 layers.

Therefore, total no. bags can be stored = Total bag in one layer X Total no. of layers:
=> 240 X 15 = 3600 Bags of cement

Hence, The answer should be 3600 bags.

Floor area of the warehouse for 2 number of piles will be:
length = 15 - 0.6 = 14.4.
And breath b = 5.6 - 0.6 - 1 = 4 m.

Because the standard of the gap between two piles is 1 m so area = 14.4 * 4 = 57.6 sqm. And the area of one bag cement 0.3 sqm. So the number of the bag in one layer = 57.6/0.3 = 192 bags and for 2.7 m height mean 15 layers of bags.

So the total number of bags will be 192 * 15 = 2880.

Density of cement is 0.035 cum.
And height of pile means the depth of ware house.
Length and breadth of the ware house is given,

For the volume of the ware house (length x breadth x height).
= 15 x 5.6 x 2.7.
= 226.8 cum.

Total quantity of cement = 226.8/0.035.
= 6480cum.
In two row it contains = 3240cum cement total.
So 3000 is suitable option for that because it can contain more than 2000 and less than 4000.

Hi guys, you have a room dimension, but nobody doing deduction properly, between the piles diff should be 1.2 m and 0.30 m from both side wall, but in width. Both side wall deduction. After the deduction, you have the answer, approximately 3600.

Length = 15-0.6 = 14.4m.
Breadth=5.6-0.6-0.8=4.2m.
0.8 less for gap b/w two piles.
Area=14.4*4.2=60.48sq.m.
No.of bag in one layer=60.48/0.3=201.6bags.
0.3 area of one bag cement.
2.7/0.18 = 15.
0.18 is the height of one bag cement.
Then, 201.6 * 15=3024 bags -> 3000 bags.

7 bags for 1 cum concrete.

15 * 5.6 * 2.7 = 226.8 cum.
226.8 * 7 = 1587.6 cum for 1 pile.

For 2 piles 2 * 1587.6 = 3175.2 bags.