Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 2 (Q.No. 37)
37.
The internal dimensions of a ware house are 15 m x 5.6 m, and the maximum height of piles is 2.70 m, the maximum number of bags to be stored in two piles, are
Discussion:
45 comments Page 5 of 5.
Prashant sp said:
3 years ago
Concept :
Generally, 0.6m is taken as the distance from the external walls and 0.8 is the gap between piles.
Calculation :
Given :
Length = 15 m, Breadth = 5.6 m, and Height of Pile = 2.70 m.
Considering the distance from the external wall and the gap between piles,
Length = 15 - 0.6 - 0.6 = 13.8 m,
Breadth = 5.6 - 0.6 - 0.6 - 0.8 = 3.6 m,
Area = 13.8 * 3.6 = 49.68 m2.
Area of one cement bag = 0.3 m2.
Height of one cement bag = 0.15 m.
No. of bags = Space for cement/Volume of one cement bag
Number of Bags = (49.68 * 2.7)/(0.3 * 0.15) = 2980 bags = 3000 Bags.
Generally, 0.6m is taken as the distance from the external walls and 0.8 is the gap between piles.
Calculation :
Given :
Length = 15 m, Breadth = 5.6 m, and Height of Pile = 2.70 m.
Considering the distance from the external wall and the gap between piles,
Length = 15 - 0.6 - 0.6 = 13.8 m,
Breadth = 5.6 - 0.6 - 0.6 - 0.8 = 3.6 m,
Area = 13.8 * 3.6 = 49.68 m2.
Area of one cement bag = 0.3 m2.
Height of one cement bag = 0.15 m.
No. of bags = Space for cement/Volume of one cement bag
Number of Bags = (49.68 * 2.7)/(0.3 * 0.15) = 2980 bags = 3000 Bags.
(16)
Njr said:
2 years ago
2100 for a single pile.
So, the right answer is 2500.
So, the right answer is 2500.
(1)
Jivan shahi said:
2 years ago
The Width of Pile = 1.6m,
So, width of warehouse = 5.6 - 1.6 = 4
Now volume=15 * 4* 2.7 = 162
Now, the volume of one bag = .054.
So, 162/.054 = 3000 bags.
So, width of warehouse = 5.6 - 1.6 = 4
Now volume=15 * 4* 2.7 = 162
Now, the volume of one bag = .054.
So, 162/.054 = 3000 bags.
(3)
Satyam said:
2 years ago
L = 15-0.6-0.6 = 13.8
B = 5.6 - 0.6 - 0.6 = 4.4
H = 2.7
13.8 × 4.4 × 2.7/0.3 × 0.18 = 3000 bag.
B = 5.6 - 0.6 - 0.6 = 4.4
H = 2.7
13.8 × 4.4 × 2.7/0.3 × 0.18 = 3000 bag.
(6)
Taba Tallum said:
2 months ago
As per IS 4082:1996, (i) minimum clear space around or between the exterior wall face and the stacks should be 600 mm, (ii) Maximum width of the stack should not be more than 3.0 m and (iii) the maximum height of stacks should not be more than 1.40 m.
No of piles stack or row or column = 2 nos.
Effective length of the stack = 15-2 x 0.3 = 14.4m,
Effective width of the stack = 5.6-0.3 x 2-0.75 = 4.25m,
Height of pile stacks = 2.70m,
We know that, plan area of each bag of cement = 0.3 m^2.
Height of each bag of cement = 0.18 m.
The Maximum number of bags of cement that can be stored in two piles = (14.4x4.25x2.7)/(0.3x0.18)
= 3060 bags ~3000 bags.
No of piles stack or row or column = 2 nos.
Effective length of the stack = 15-2 x 0.3 = 14.4m,
Effective width of the stack = 5.6-0.3 x 2-0.75 = 4.25m,
Height of pile stacks = 2.70m,
We know that, plan area of each bag of cement = 0.3 m^2.
Height of each bag of cement = 0.18 m.
The Maximum number of bags of cement that can be stored in two piles = (14.4x4.25x2.7)/(0.3x0.18)
= 3060 bags ~3000 bags.
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