Civil Engineering - Concrete Technology - Discussion

Width of gallery = .6m,
So, width of warehouse = 5.6 - .6 = 5.
Now volume=15 * 5 * 2.7 = 202.5.
Now, the volume of one bag=.054.
So, 202.5/.054 = 3750 bags.

Concept :
Generally, 0.6m is taken as the distance from the external walls and 0.8 is the gap between piles.

Calculation :
Given :

Length = 15 m, Breadth = 5.6 m, and Height of Pile = 2.70 m

Considering the distance from external wall and gap between piles,

Length = 15 - 0.6 - 0.6 = 13.8 m,
Breadth = 5.6 - 0.6 - 0.6 - 0.8 = 3.6 m,
Area = 13.8 * 3.6 = 49.68 m2,
Area of one cement bag = 0.3 m2,
Height of one cement bag = 0.15 m,
No. of bags = Space for cement/Volume of one cement bag.
Number of Bags = (49.68 *2.7)/(0.3* 0.15) = 2980 bags = 3000 Bags.

Effective area of hall = 15 x (5.6- 0.6 * 3) = 57m
Area of a cement bag = 0.3 sqm.
No. of cement bag in one layer = 57/.3 = 190,
Height of pile = 0.7.
No. of layer Height of one cement bag = 2.7/0.18 = 15 layer,
Total no. of bags 15 * 90 = 2850 bags.

The answer should be 30 bags. Because It's not possible for 2 pile to contain 3000 bags.

Height of pile=2.7.
Plain area for 1 bag=0.3,
Total piles=2.
Volume of 2 piles=2*0.3*2.7=1.62,

Volume of 1 bag for storage =0.3*0.18=0.054.

Number of the bag in 2 piles=1.62/0.054=30.

No of bags in single layer= 15 * 5.6 * 0.8/0.3= 224.
No of bags along with height = 270/18 =15.
Total no of bags= 224*15 = 3360 max.
Area for storage of cement can max be only 80% of the room area. So, here, the correct option is 3000.

Effective dimentions are,

Horizontal clearance 0.3 m
15 - 2*0.3=14.4m,
5.6 - 2*0.3= 5m.

Now vertical clearance 0.2 m from top and bottom.
Therefore 2.7-2*0.2 = 2.3m.
Therefore volume of warehouse= 14.4 * 5 * 2.3 = 165.6 m3.
Area of 1 bag= 0.3 m2.

And the height of 1 bag = 0.18m.
So,the volume of bag= 0.3 * 0.18 = 0.054 m3.
Now, max no of the bag can be stored= volume of warehouse ÷ volume of the bag.
= 165.6 ÷ 0.054 = 3066.6667 bags.

(15-0.6-0.6)*(5.6-0.6-0.6)*1.8÷(.3*18) = 2024 bags.

0.6m is the distance from the external wall from all the four sides.

1.8 m is taken instead of 2.7 m because maximum of 10 bags of cement can be stacked in a stack.

0.18 m = 18 cm Height of cement bag.
0.3m^2 = 3000cm^2 = Surface area of cement bag.

But if the height is taken as 2.7m then the answer becomes 3036 bags.

@Pratik.

0.3 m^2 floor space of 1 bag of cement.

What amount of floor space will one bag of cement occupy? Tell me.

Length=15-.6=14.4m.
The gap between pile 1.6 m.
So breath= 5.6-.6-1.6=3.4m.
area for cement=14.4*3.4=49.64m2.
No of bag stored= (49.64*2.7)/(.3*.18) = 2482~2500 is the correct answer.