Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 2 (Q.No. 17)
17.
Water required per bag of cement, is
7 kg
14 kg
21 kg
28 kg
35 kg
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
45 comments Page 1 of 5.

Naren said:   8 years ago
In general:-

Grade minimum w/c water required(lit/bag)
M10 -------> 0.6. ------- 34 (30+4 lit extra)
M15 -------> 0.6 ------- 32 (30+2 lit extra)
M20 -------> 0.55 ------- 30 (28+2.")
M25 -------> 0.5 ------- 27 (25+2.".)
M30/35 -------> 0.45 ------- 25 (23+2.".)
M30 -------> 0.4 ------- 22 (20+2. ".)
Minmum -------> 0.38 ------- 21 (19+2. ".)

Gopinathan said:   6 years ago
Tri-calcium silicate requires 24% and Dicalcium silicate requires 21% (only weight of Cement)
Average of 23% of water by weight of cement is required for chemical reaction with portland cement compound.

15% by weight of cement is required to fill up gel- pores.
Total requirements of water is 23 + 15= 38%.

Vishal said:   1 decade ago
Normally 38% of water is required combinding bond water and gel water to hydrate cement. So 50*38/100 = 19 lit water minimum. But for concrete mix the w/c ratio is 45% hence for OPC it should be 27 lit/bag and for ppc it should be 25 lit/bag required.

DARSHAN H A said:   9 years ago
Maximum water-cement ratio as per IS10262 : 2009 is 0.55 And minimum water cement ratio is 0.38. It cannot be 35 kg. W/C ratio depends on the exposure condition of concrete but minimum water cement ratio is 0.38 for full hydration of concrete.

Bapi khan said:   9 years ago
The unit is wrong. It should be 35 lit water is required for 1 bag cement where as 22.5 kg water is required for 1 bag cement.
1 m^3 = 1000 lit.
Then find 0.0347 m^3= ? lit.
Ans will be 34.7 lit = 35 lit.

Rahul Kumar said:   9 years ago
Generally, we use 35% water of cement.
Then 1 beg cement means 50 kg cement and 35% of 50 kg is 50*35/100= 17.5 kg should be maximum 21 kg water.

Then w/c is 21/50 = .42, Thus C is the correct answer.

Jayrajsinh Parmar said:   8 years ago
Cement 500= 0.35 m3 (50 kg cement =0.035 m3 cement)

Water Req for cement 38 %
= 0.35 * 38/woo
= 0.133 m3 Water

From Water Density.
1000 kg/m3 = (kg/0.133 m3)

Water = 133 kg.

Sham Chavan said:   6 years ago
1m^3 = 1000kg or 1000lit.
1m^3 = density of cement / weight of one bag.
1m^3 = 1440/50=28.8 bags.
28.8bags = 1000kg.
1bag = 1000/28.8 = 34.7~ 35kg or 35 lit.
So Answer is correct.
(9)

Pavan@iiit nuzvid said:   6 years ago
Simple,

Vol of cement bag of 50 Kg = 0.035 m3.
And, per 1 m3 we need 1000Kg of water.
So, Water required = 1000*0.035 = 35 Kg.
Since there is no mention about w/c ratio.
(16)

Nikhil Dev said:   7 years ago
The maximum quantity of water = 65% of the weight of cement.
i.e 65/100*50 = 32 litre.

Hence, 32 litre is the correct answer.


Post your comments here:

Your comments will be displayed after verification.