Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 4 (Q.No. 2)
2.
If aggregates completely pass through a sieve of size 75 mm and are retained on a sieve of size 60 mm, the particular aggregate will be flaky if its minimum dimension is less than
Discussion:
13 comments Page 1 of 2.
Lalit said:
4 years ago
Flaky aggregate = 3/5 of there's mean dimension.
= (3/5) *{(75+60) /2}.
= (3/5) *(67.5).
= 40.5mm.
= (3/5) *{(75+60) /2}.
= (3/5) *(67.5).
= 40.5mm.
(7)
Abhi said:
7 years ago
Flakiness means 3/5 of mean size of aggregate, therefore it is 40.5.
(1)
Sandeep kumar said:
6 years ago
Since we know.
Flakiness index= .6(3/5)* average size of aggregate((passing size+retained size)/2).
So it is 40.5mm.
Flakiness index= .6(3/5)* average size of aggregate((passing size+retained size)/2).
So it is 40.5mm.
(1)
Avijit mirdda said:
6 years ago
Average of 75mm and 60 mm sieve is (75+60)/2=67.5.
For flaky if its minimum dimension is less than 3/5 of 67.5 i.e. 67.5*(3/5) = 40.5mm.
For flaky if its minimum dimension is less than 3/5 of 67.5 i.e. 67.5*(3/5) = 40.5mm.
(1)
Anurag said:
4 years ago
An aggregate is said to be flaky if its least dimension is less that 3-5.
That's why we use 3÷5.
That's why we use 3÷5.
(1)
Reddy said:
1 decade ago
60+75 = 135.
135/2 = 67.5.
3/5*67.5 = 40.5.
135/2 = 67.5.
3/5*67.5 = 40.5.
ARUNA said:
9 years ago
(75+60)/2 = 67.5.
67.5*3/5 = 40.5.
67.5*3/5 = 40.5.
Prahumac said:
9 years ago
I didn't get it why did you multiply by 3.
ITAF HUSSAIN said:
9 years ago
@prahumac we multiply it by 3/5 of its mean dimension
G.V.S. Bhargav said:
9 years ago
Flaky aggregate is a aggregate having a size less than 60% of average size of the two aggregate.
So now (75+60)/2 = 67.5.
Now 60% of 67.5 is,
That is 67.5*(60/100) = 40.5.
So now (75+60)/2 = 67.5.
Now 60% of 67.5 is,
That is 67.5*(60/100) = 40.5.
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