# Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 4 (Q.No. 2)

2.

If aggregates completely pass through a sieve of size 75 mm and are retained on a sieve of size 60 mm, the particular aggregate will be flaky if its minimum dimension is less than

Discussion:

13 comments Page 1 of 2.
Lalit said:
5 years ago

Flaky aggregate = 3/5 of there's mean dimension.

= (3/5) *{(75+60) /2}.

= (3/5) *(67.5).

= 40.5mm.

= (3/5) *{(75+60) /2}.

= (3/5) *(67.5).

= 40.5mm.

(15)

Abhi said:
7 years ago

Flakiness means 3/5 of mean size of aggregate, therefore it is 40.5.

(1)

Sandeep kumar said:
7 years ago

Since we know.

Flakiness index= .6(3/5)* average size of aggregate((passing size+retained size)/2).

So it is 40.5mm.

Flakiness index= .6(3/5)* average size of aggregate((passing size+retained size)/2).

So it is 40.5mm.

(1)

Avijit mirdda said:
7 years ago

Average of 75mm and 60 mm sieve is (75+60)/2=67.5.

For flaky if its minimum dimension is less than 3/5 of 67.5 i.e. 67.5*(3/5) = 40.5mm.

For flaky if its minimum dimension is less than 3/5 of 67.5 i.e. 67.5*(3/5) = 40.5mm.

(1)

Anurag said:
4 years ago

An aggregate is said to be flaky if its least dimension is less that 3-5.

That's why we use 3Ã·5.

That's why we use 3Ã·5.

(1)

Reddy said:
1 decade ago

60+75 = 135.

135/2 = 67.5.

3/5*67.5 = 40.5.

135/2 = 67.5.

3/5*67.5 = 40.5.

ARUNA said:
1 decade ago

(75+60)/2 = 67.5.

67.5*3/5 = 40.5.

67.5*3/5 = 40.5.

Prahumac said:
1 decade ago

I didn't get it why did you multiply by 3.

ITAF HUSSAIN said:
1 decade ago

@prahumac we multiply it by 3/5 of its mean dimension

G.V.S. Bhargav said:
9 years ago

Flaky aggregate is a aggregate having a size less than 60% of average size of the two aggregate.

So now (75+60)/2 = 67.5.

Now 60% of 67.5 is,

That is 67.5*(60/100) = 40.5.

So now (75+60)/2 = 67.5.

Now 60% of 67.5 is,

That is 67.5*(60/100) = 40.5.

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