Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 4 (Q.No. 2)
If aggregates completely pass through a sieve of size 75 mm and are retained on a sieve of size 60 mm, the particular aggregate will be flaky if its minimum dimension is less than
20.5 mm
30.5 mm
40.5 mm
50.5 mm
none of these.
Answer: Option
No answer description is available. Let's discuss.
13 comments Page 1 of 2.

Abbas khan said:   2 years ago
If an aggregate is rounded or angular then what value will be use about dimension? Please explain.

Anurag said:   4 years ago
An aggregate is said to be flaky if its least dimension is less that 3-5.

That's why we use 3÷5.

Lalit said:   4 years ago
Flaky aggregate = 3/5 of there's mean dimension.
= (3/5) *{(75+60) /2}.
= (3/5) *(67.5).
= 40.5mm.

Yasir said:   5 years ago
Flakiness means 60%(3/5) of avg size of particles.

Avijit mirdda said:   6 years ago
Average of 75mm and 60 mm sieve is (75+60)/2=67.5.

For flaky if its minimum dimension is less than 3/5 of 67.5 i.e. 67.5*(3/5) = 40.5mm.

Sandeep kumar said:   6 years ago
Since we know.

Flakiness index= .6(3/5)* average size of aggregate((passing size+retained size)/2).
So it is 40.5mm.

Abhi said:   7 years ago
Flakiness means 3/5 of mean size of aggregate, therefore it is 40.5.

Sankalp kadam said:   7 years ago
If avg has be taken into account then according to me, as agg are retained on 60mm sieve size so it means that most of the agg are retained at 60 so we have to consider that value only rather than taking commutative of two sieve sizes isn't it?

Means (3/5) * 60 that comes 36mm.

G.V.S. Bhargav said:   9 years ago
Flaky aggregate is a aggregate having a size less than 60% of average size of the two aggregate.

So now (75+60)/2 = 67.5.

Now 60% of 67.5 is,

That is 67.5*(60/100) = 40.5.

ITAF HUSSAIN said:   9 years ago
@prahumac we multiply it by 3/5 of its mean dimension

Post your comments here:

Your comments will be displayed after verification.