Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 1 (Q.No. 2)
2.
If 1500 g of water is required to have a cement paste 1875 g of normal consistency, the percentage of water is,
Discussion:
95 comments Page 6 of 10.
Mohd sarfraz said:
1 decade ago
It is very simple water percentage is 25 If any guy doubt it than any other contact me than I will prove it.
Najrul said:
10 years ago
Wt of cement = 1875-1500 = 375.
Wt of water = 1500.
% of water required = 375/1500*100 = 25% answer.
Wt of water = 1500.
% of water required = 375/1500*100 = 25% answer.
Tony said:
1 decade ago
But, weight of water is 1500g.
So % = Weight of water/Weight of paste*100.
= 1500/1875*100 = 80%.
So % = Weight of water/Weight of paste*100.
= 1500/1875*100 = 80%.
Dorna said:
4 years ago
How the % of water = wt of cement/wt of water, is this formula is right? Anyone explain me, please.
(3)
GAURAV GIRI said:
1 decade ago
Weight of cement = 1875-1500 = 375.
So % of water = 375/wt of water.
= 375/1500*100.
= 25%.
So % of water = 375/wt of water.
= 375/1500*100.
= 25%.
Ewunetu Molla said:
6 years ago
Cement paste= water +cement = 1875g,
Amount of water =1500g,
%Water = (1875-1500)/1500 = 25%.
Amount of water =1500g,
%Water = (1875-1500)/1500 = 25%.
Mohamad said:
10 years ago
I agree with my colleagues that the question is wrong.
The water weight should be 375 gram.
The water weight should be 375 gram.
Chethan said:
8 years ago
As per code, w/c ratio has not exceeded 1 so wt of water should be less than wt of cement.
Upender said:
7 years ago
Percentage of water = weight of cement/weight of water * 100 =1875-1500/1500 * 100= 25%.
Koteswararao said:
1 decade ago
Weight of cement = 1875-1500 = 375.
Weight of water = 1500.
w/c = 375/1500*100 = 25%.
Weight of water = 1500.
w/c = 375/1500*100 = 25%.
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