Chemical Engineering - Process Control and Instrumentation - Discussion
Discussion Forum : Process Control and Instrumentation - Section 1 (Q.No. 23)
23.
The closed loop pole of a stable second order system could be
Discussion:
11 comments Page 1 of 2.
Omprakash hada said:
9 years ago
For a closed loop transfer function, roots of the numerator are called zeros and roots of the denominator are called poles. So for stable response poles should be real and negative. So correct option is C.
Ramakanth Reddy said:
10 years ago
For a stable system a closed loop pole should lie to the left of the imaginary axis for that it should be real and negative.
Jasraj said:
8 years ago
Answer should be C for the stable system all poles should be located in the left half of the S plane.
Dumbi Boipai said:
1 decade ago
For a Stable system, pole should have negative real part. So the answer should be 'C' not 'A'.
Nourabunar said:
8 years ago
Should be C, Should be negative to be having value in final value theorem.
Amit said:
7 years ago
Criteria for stability is atleast 1 negative pole. So the answer is C.
Nomi said:
10 years ago
Pool should be negative and so right answer should be C.
Suraj said:
9 years ago
Only C left side axis to stable.
Ujjwala bhondave said:
7 years ago
Yeah, C is correct. I agree.
Kajol ohol said:
7 years ago
The Answer should be C.
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