Chemical Engineering - Process Control and Instrumentation - Discussion

Discussion Forum : Process Control and Instrumentation - Section 1 (Q.No. 23)
23.
The closed loop pole of a stable second order system could be
both real and positive.
complex conjugate with positive real parts.
both real and negative.
one real positive and the other real negative.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

Amit said:   7 years ago
Criteria for stability is atleast 1 negative pole. So the answer is C.

Ujjwala bhondave said:   7 years ago
Yeah, C is correct. I agree.

Kajol ohol said:   7 years ago
The Answer should be C.

Jasraj said:   8 years ago
Answer should be C for the stable system all poles should be located in the left half of the S plane.

Nourabunar said:   8 years ago
Should be C, Should be negative to be having value in final value theorem.

Prince babu said:   9 years ago
Answer should be C.

Omprakash hada said:   9 years ago
For a closed loop transfer function, roots of the numerator are called zeros and roots of the denominator are called poles. So for stable response poles should be real and negative. So correct option is C.

Suraj said:   9 years ago
Only C left side axis to stable.

Ramakanth Reddy said:   10 years ago
For a stable system a closed loop pole should lie to the left of the imaginary axis for that it should be real and negative.

Nomi said:   10 years ago
Pool should be negative and so right answer should be C.


Post your comments here:

Your comments will be displayed after verification.