Chemical Engineering - Process Control and Instrumentation - Discussion
Discussion Forum : Process Control and Instrumentation - Section 1 (Q.No. 23)
23.
The closed loop pole of a stable second order system could be
Discussion:
11 comments Page 1 of 2.
Dumbi Boipai said:
1 decade ago
For a Stable system, pole should have negative real part. So the answer should be 'C' not 'A'.
Nomi said:
10 years ago
Pool should be negative and so right answer should be C.
Ramakanth Reddy said:
10 years ago
For a stable system a closed loop pole should lie to the left of the imaginary axis for that it should be real and negative.
Suraj said:
9 years ago
Only C left side axis to stable.
Omprakash hada said:
9 years ago
For a closed loop transfer function, roots of the numerator are called zeros and roots of the denominator are called poles. So for stable response poles should be real and negative. So correct option is C.
Prince babu said:
9 years ago
Answer should be C.
Nourabunar said:
8 years ago
Should be C, Should be negative to be having value in final value theorem.
Jasraj said:
8 years ago
Answer should be C for the stable system all poles should be located in the left half of the S plane.
Kajol ohol said:
7 years ago
The Answer should be C.
Ujjwala bhondave said:
7 years ago
Yeah, C is correct. I agree.
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