Chemical Engineering - Process Control and Instrumentation - Discussion
Discussion Forum : Process Control and Instrumentation - Section 3 (Q.No. 27)
27.
The calibration data of a thermocouple with its cold junction at 0°C are given below.
The hot junction of the thermocouple is placed in a bath at 80°C, while its cold junction is at 20°C. What is the emf of thermocouple ?
The hot junction of the thermocouple is placed in a bath at 80°C, while its cold junction is at 20°C. What is the emf of thermocouple ?
Discussion:
4 comments Page 1 of 1.
Asif Sayed said:
1 decade ago
I didn't understand. How it's comes 2.46 mV?
Hari said:
1 decade ago
emf(80)-emf(20) = 3.26-0.80 = 2.46.
Jayvin said:
10 years ago
Temperature difference is 80-20=60 and at 60 emf generate is 2.43. So right answer is 2.43.
Rithik said:
7 years ago
The hot junction of the thermocouple is placed in a bath at 80°C and the cold junction is at 20°C.
The EMF of thermocouple=emf(hot junction)-emf(cold junction),
=emf(80)-emf(20) = 3.26-0.80,
= 2.46 mv.
The EMF of thermocouple=emf(hot junction)-emf(cold junction),
=emf(80)-emf(20) = 3.26-0.80,
= 2.46 mv.
(1)
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