Chemical Engineering - Mass Transfer - Discussion

Discussion Forum : Mass Transfer - Section 1 (Q.No. 2)
2.
In a solution containing 0.30 Kg mole of solute and 600 kg of solvent, the molality is
0.50
0.60
2
1
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
21 comments Page 1 of 3.

Poonam Rathod said:   1 decade ago
Molality = (solute/solvent) *100.

= (0.30/600) *1000.

= 0.50
(1)

Lilian said:   1 decade ago
What is the formular for molarity ?

Abdulrazaq said:   1 decade ago
Molality = (solute/solvent) *100.

= (0.30/600) *1000.

Base on what change from 100 to 1000

Ram said:   1 decade ago
Molality= (Wt.of Sloute*1000)/(Mol.wt * Wt of the slovent)
(1)

Deepak Bhengra said:   1 decade ago
Molality is defined as the number of moles of solute dissolved in 1 liter of solvent.

Hence, molality = (no.of solute/no.of solvent) *1000.

= (0.3/600) *1000.

= 0.50.
(1)

Satish said:   1 decade ago
Molality = Number of grm moles of solute per kilogram of solvent.

= 0.3*1000/600=0.5m

Anurag said:   1 decade ago
Gram mole of solute per kilogram of solvent = Molality.

Sandy said:   1 decade ago
Molality is differ from molarity.

Molality is no.of moles of solute present in kg of solvent.

So Molality = (wt.of solute/molecular wt.of solute)*(1000/wt.of solvent).

Molarity is not based on wt.of solvent it based on volume.

Molarity= (wt.of solute/molecular wt.of solute)*(1000/volume of solution).

Molality of given pro is (0.3*1000) /600 = 0.5.

Rajesh said:   1 decade ago
Molality = Number of gram moles of solute per kilogram of solvent.

Omkar said:   1 decade ago
Molality = Number of gram moles of solute per kilogram of solvent.

Molality= 0.3 x 1000 / 600 = 0.5.

1 kg = 1000 gm thats why it is multiplied by 1000.


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