Chemical Engineering - Mass Transfer - Discussion
Discussion Forum : Mass Transfer - Section 1 (Q.No. 2)
2.
In a solution containing 0.30 Kg mole of solute and 600 kg of solvent, the molality is
Discussion:
21 comments Page 1 of 3.
Sandy said:
1 decade ago
Molality is differ from molarity.
Molality is no.of moles of solute present in kg of solvent.
So Molality = (wt.of solute/molecular wt.of solute)*(1000/wt.of solvent).
Molarity is not based on wt.of solvent it based on volume.
Molarity= (wt.of solute/molecular wt.of solute)*(1000/volume of solution).
Molality of given pro is (0.3*1000) /600 = 0.5.
Molality is no.of moles of solute present in kg of solvent.
So Molality = (wt.of solute/molecular wt.of solute)*(1000/wt.of solvent).
Molarity is not based on wt.of solvent it based on volume.
Molarity= (wt.of solute/molecular wt.of solute)*(1000/volume of solution).
Molality of given pro is (0.3*1000) /600 = 0.5.
PATEL ANAND said:
5 years ago
Morality is defined as,
Molality=(solute (gram)/mass of solvent in kg)
=> volume density of solution is kg/10000.
So, 600/1000= 0.600.
M=0.3 kg/0.600liter=0.30*0.600=0.50 kmol/litre.
Molality=(solute (gram)/mass of solvent in kg)
=> volume density of solution is kg/10000.
So, 600/1000= 0.600.
M=0.3 kg/0.600liter=0.30*0.600=0.50 kmol/litre.
(1)
Ahmed Gamal Fayed said:
7 years ago
Density of water = 1000 kg/m3 {g/liter}.
Volume of solution = kg/ density.
= 600/ 1000 = 0.6 liter.
M = 0.3 kg/0.6 liter = 0.50 kg mole/ liter.
Volume of solution = kg/ density.
= 600/ 1000 = 0.6 liter.
M = 0.3 kg/0.6 liter = 0.50 kg mole/ liter.
(2)
Deepak Bhengra said:
1 decade ago
Molality is defined as the number of moles of solute dissolved in 1 liter of solvent.
Hence, molality = (no.of solute/no.of solvent) *1000.
= (0.3/600) *1000.
= 0.50.
Hence, molality = (no.of solute/no.of solvent) *1000.
= (0.3/600) *1000.
= 0.50.
(1)
Omkar said:
1 decade ago
Molality = Number of gram moles of solute per kilogram of solvent.
Molality= 0.3 x 1000 / 600 = 0.5.
1 kg = 1000 gm thats why it is multiplied by 1000.
Molality= 0.3 x 1000 / 600 = 0.5.
1 kg = 1000 gm thats why it is multiplied by 1000.
Arshad Ali said:
7 years ago
Molality=(mol of solute/Kg of solvent).
So, 0.30 kg mol=0.30*1000 mol= 300 mol,
Hence, Molality = 300mol/600Kg=0.5 mol/Kg.
So, 0.30 kg mol=0.30*1000 mol= 300 mol,
Hence, Molality = 300mol/600Kg=0.5 mol/Kg.
(7)
Om pal said:
1 year ago
Molality = gram moles of Salute/mass of solute in kg.
Then, 0.30 * 1000/600 = 300.00/600 = 1/2 = 0.50 answer.
Then, 0.30 * 1000/600 = 300.00/600 = 1/2 = 0.50 answer.
(3)
Abdulrazaq said:
1 decade ago
Molality = (solute/solvent) *100.
= (0.30/600) *1000.
Base on what change from 100 to 1000
= (0.30/600) *1000.
Base on what change from 100 to 1000
Raj said:
8 years ago
Molality = (kg solute/kg solvent)*100.
= (.3/600)*1000.
= 0.5.
= (.3/600)*1000.
= 0.5.
(2)
Amit Kaushik said:
7 years ago
Molality = (gmol of solute/Mass of Solvent in Kg).
So, Molality = (.3 * 1000)/600 = 0.5.
So, Molality = (.3 * 1000)/600 = 0.5.
(1)
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