Chemical Engineering - Mass Transfer - Discussion
Discussion Forum : Mass Transfer - Section 1 (Q.No. 2)
2.
In a solution containing 0.30 Kg mole of solute and 600 kg of solvent, the molality is
Discussion:
21 comments Page 3 of 3.
Om pal said:
1 year ago
Molality = gram moles of Salute/mass of solute in kg.
Then, 0.30 * 1000/600 = 300.00/600 = 1/2 = 0.50 answer.
Then, 0.30 * 1000/600 = 300.00/600 = 1/2 = 0.50 answer.
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