Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 28)
28.
X can do a piece of work in 40 days. He works at it for 8 days and then Y finished it in 16 days. How long will they together take to complete the work?

13 1 days
3

15 days
20 days
26 days
Answer: Option
Explanation:

Work done by X in 8 days = ( 1 x 8 ) = 1 .
40 5

Remaining work = ( 1 - 1 ) = 4 .
5 5

Now, 4 work is done by Y in 16 days.
5

Whole work will be done by Y in ( 16 x 5 ) = 20 days.
4

Therefore X's 1 day's work = 1 , Y's 1 day's work = 1 .
40 20

(X + Y)'s 1 day's work = ( 1 + 1 ) = 3 .
40 20 40

Hence, X and Y will together complete the work in ( 40 ) = 13 1 days.
3 3

Discussion:
33 comments Page 3 of 4.

Ganesh kumar said:   6 years ago
How 4/5 becomes into 5/4?

Please clarify it.
(1)

Sutha said:   7 years ago
How 4/5 becomes into 5/4. Please clarify it.

Atul said:   6 years ago
Wonderful explanation, thanks @Mohit.
(1)

Sandya bujji said:   1 decade ago
Ok thank you friends I understood.

Gobind Mandal said:   9 years ago
Why did you convert 4/5 to 5/4?

Ashis said:   7 years ago
Thanks for the solution @Mohit.

Prashant singh said:   7 years ago
How 3/40 is converted to 40/3?

Keerthi said:   1 decade ago
How to solve using LCM method?

Bala said:   1 decade ago
Why you convert 4/5 into 5/4?

Heena roy said:   1 decade ago
X's 1 day work 1/40 ? how ?


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