Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 13)
13.
A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?
Answer: Option
Explanation:
(A + B)'s 20 day's work = | ![]() |
1 | x 20 | ![]() |
= | 2 | . |
30 | 3 |
Remaining work = | ![]() |
1 - | 2 | ![]() |
= | 1 | . |
3 | 3 |
Now, | 1 | work is done by A in 20 days. |
3 |
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
Discussion:
63 comments Page 5 of 7.
Srishailam said:
1 decade ago
Am not understanding this problem any body please help me.
How A work come 20 days. Explain ?
How A work come 20 days. Explain ?
Rintu Adhikary said:
9 years ago
What is the answer if the question is " in how many days can B alone finish the work?
Dhruv said:
1 decade ago
How come 1/3 work is done in 20 days should the work in 20 days not be 2/3?
Pooja bhardwaj said:
8 years ago
Thank you for the best and easy explanation @Kaaly and @Senchu Thomas.
Ars said:
1 decade ago
In question it self given that A did the remaining work in 20 days.
Manmohan said:
9 years ago
Why we can take t*d?
But some problems we can take pages/time.
But some problems we can take pages/time.
Sumit said:
9 years ago
Its short tricks X * P/X - Y = 30 * 20/30 - 20 = 600/10 = 60.
Sandip said:
3 years ago
Still, I can't understand this. Can anyone help me to get it?
(4)
HB Rajputh said:
2 years ago
I'm not getting it, please help me by explaining in detail.
(5)
PANKAJ PARIHAR said:
8 years ago
What is the total time taken by B? Please answer it.
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