Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 13)
13.
A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?
Answer: Option
Explanation:
| (A + B)'s 20 day's work = |  |
1 | x 20 |  |
= | 2 | . |
| 30 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 20 days. |
| 3 |
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
Discussion:
63 comments Page 4 of 7.
Manikandan said:
1 decade ago
@kulbhushan
Already 20 days work finished by A and B.Remaining 10 days work done by A in 20 days. If A alone able to finish 30 days work in 60days.
Already 20 days work finished by A and B.Remaining 10 days work done by A in 20 days. If A alone able to finish 30 days work in 60days.
Anitha said:
2 years ago
A + B = 1/30
B only work 20 days after leaving;
B=1/20,
A+1/20 = 1/30
A = 1/20-1/30
A = 30-20/600
A = 10/600
A = 1/60
So, A Worked alone 60 days.
B only work 20 days after leaving;
B=1/20,
A+1/20 = 1/30
A = 1/20-1/30
A = 30-20/600
A = 10/600
A = 1/60
So, A Worked alone 60 days.
(44)
Arya said:
8 years ago
A + B = 1/30 its entire work But
A + B work together only for 20 days so...
A + B - A
1/30 - 1/20
LCM is 60.
So, 2 - 3 ÷60.
1/60 = 60 Days.
A + B work together only for 20 days so...
A + B - A
1/30 - 1/20
LCM is 60.
So, 2 - 3 ÷60.
1/60 = 60 Days.
Ankush said:
1 decade ago
Now, 1 work is done by A in 20 days. 3 Therefore, the whole work will be done by A in (20 x 3) = 60 days.
Please can anyone explain me this.
Please can anyone explain me this.
Bantu Venkatesh said:
6 years ago
Together 1/30*20=2/3.
2parts work completed.
Remaining 1 part 'A'completed in 20days.
1part work 20days.
3 prts --------?.
3 * 20 = 60 days.
2parts work completed.
Remaining 1 part 'A'completed in 20days.
1part work 20days.
3 prts --------?.
3 * 20 = 60 days.
(2)
Ash said:
9 years ago
And what we do if the whole work was done by B alone. Then the answer should remain the same or will be changed?
Please answer me.
Please answer me.
Srj Jaiswal said:
6 years ago
Hello,
A+b = 60/30 =>2
B=60/20 =>3
60 is total work.
A+b=2,
A+3=2,
A=1.
So, A divided total work.
A=60/1.
= 60ans.
A+b = 60/30 =>2
B=60/20 =>3
60 is total work.
A+b=2,
A+3=2,
A=1.
So, A divided total work.
A=60/1.
= 60ans.
(1)
Kaaly said:
1 decade ago
" very simple explanation "
Total work = (A+B) = 1/30.
B left the work = 1/20.
B -(A+B) = 1/20-1/30 = 1/60.
Total work = (A+B) = 1/30.
B left the work = 1/20.
B -(A+B) = 1/20-1/30 = 1/60.
VANI said:
1 decade ago
@Ankush.
Here in question said that 1/3 work is done by A after another 20 days. So we done 20*3.
Here in question said that 1/3 work is done by A after another 20 days. So we done 20*3.
E ABHILASH GOWD said:
8 years ago
A+B =30 DAYS.
B LEFT 20 DAYS.
A FINSH WORK IN 20 DAYS.
1-1/20 =19/20.
1/30-19/20 =1/60.
60 DAYS.
B LEFT 20 DAYS.
A FINSH WORK IN 20 DAYS.
1-1/20 =19/20.
1/30-19/20 =1/60.
60 DAYS.
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