Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 13)
13.
A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?
Answer: Option
Explanation:
| (A + B)'s 20 day's work = |  |
1 | x 20 |  |
= | 2 | . |
| 30 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 20 days. |
| 3 |
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
Discussion:
63 comments Page 3 of 7.
RaghavendrA naik said:
6 years ago
A and B should take 30 days completely to finish.
And they finished 20 days work.
20/30 work is over.
10/30=1/3 work remaining.
That work completed by 20days by A.
20*3=60 days required.
And they finished 20 days work.
20/30 work is over.
10/30=1/3 work remaining.
That work completed by 20days by A.
20*3=60 days required.
Soumya said:
8 years ago
Pushpa can do a work in 10 days and Komal can do in 20 days. They work together for 5 days, then komal goes away In how many days more will Pushpa finish the work?
Can anyone solve this?
Can anyone solve this?
Poorvi said:
8 years ago
Pushpas work 1/10.
Komals work. 1/20 Per day.
So, they work for 5 days.
Their total work should be calculated by 1/10 + 1/20 then -1/5 you'll get the Answer.
Hope it's correct.
Komals work. 1/20 Per day.
So, they work for 5 days.
Their total work should be calculated by 1/10 + 1/20 then -1/5 you'll get the Answer.
Hope it's correct.
Prabu said:
6 years ago
A and B together can complete a piece of work in 12 days. They worked together for 5 days and A alone finished the rest of the work in 14 days. An alone can complete the work in?
Sap said:
6 years ago
A and B together complete the project in 5 days. A alone can do the project in 8 days. How many days will B alone take to complete the same project? Can anyone solve this?
Abinesh said:
7 months ago
A + B = 30 days
Then A + B works for 20 days.
This shows that they have completed 2/3 works.
Now 1/3 of the work is done by A in 20 days.
So, 1/3 * 1/20,
= 60 days.
Then A + B works for 20 days.
This shows that they have completed 2/3 works.
Now 1/3 of the work is done by A in 20 days.
So, 1/3 * 1/20,
= 60 days.
(4)
Sanjana said:
8 years ago
To make the last step easy we can understand it as follows:
1/3work can be done in 20 days.
So, 1 wor will be don win 20 * 3 60 days (try using direct proportion)
1/3work can be done in 20 days.
So, 1 wor will be don win 20 * 3 60 days (try using direct proportion)
Godse said:
1 decade ago
a+b = 1/30.
a+b = x/20.
a = y/20.
So,
1/30 = x/20.
x = 20/30.
= 2/3.
Given,
x+y = 1.
y = 1-(2/3).
= 1/3.
Given,
a = y/20.
= 1/60.
So 60 days.
a+b = x/20.
a = y/20.
So,
1/30 = x/20.
x = 20/30.
= 2/3.
Given,
x+y = 1.
y = 1-(2/3).
= 1/3.
Given,
a = y/20.
= 1/60.
So 60 days.
Balaji rajendran said:
10 years ago
@Deepak yadav.
In this problem A can finish 10 days work in 20 days so if he left alone to do a 30 days work, he will take 60 days to finish the work.
In this problem A can finish 10 days work in 20 days so if he left alone to do a 30 days work, he will take 60 days to finish the work.
Balaji rajendran said:
10 years ago
@Raj.
B alone can finish the work in 60 days same as A.
A+B = 1/30 and A = 1/60 then B = 1/30-1/60 = 1/60. So B alone can finish the work in 60 days.
B alone can finish the work in 60 days same as A.
A+B = 1/30 and A = 1/60 then B = 1/30-1/60 = 1/60. So B alone can finish the work in 60 days.
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