Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 13)
13.
A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?
Answer: Option
Explanation:
| (A + B)'s 20 day's work = |  |
1 | x 20 |  |
= | 2 | . |
| 30 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 20 days. |
| 3 |
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
Discussion:
63 comments Page 6 of 7.
Rohit said:
8 years ago
In how many days B will complete the same work?
Kulbhushan said:
1 decade ago
Hi, how we calculated that 1/3 work in 20 days?
Arun said:
3 years ago
Why the reaming work is -1? Explain it please.
(1)
Raj said:
1 decade ago
In how many days B alone can finish the work?
Harsimran kaur said:
7 years ago
@Pankaj.
Total time taken by B is 60 days.
Total time taken by B is 60 days.
Pankaj khatikkar said:
5 years ago
Can anyone explain this with LCM method?
Sinchana Shettar said:
5 years ago
Please, Explain this with LCM method.
Poorvi said:
8 years ago
Good explanations. Thank you all.
Himanshu said:
5 years ago
Nice. Thanks all for explaining.
Deepak yadav said:
1 decade ago
Please give its short trick.
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