Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 13)
13.
A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?
Answer: Option
Explanation:
| (A + B)'s 20 day's work = |  |
1 | x 20 |  |
= | 2 | . |
| 30 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 20 days. |
| 3 |
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
Discussion:
63 comments Page 5 of 7.
Ash said:
9 years ago
And what we do if the whole work was done by B alone. Then the answer should remain the same or will be changed?
Please answer me.
Please answer me.
Gaurav said:
9 years ago
Why 1 is subtract from 2/3?
Harish said:
9 years ago
(A + B) does a piece of work in 30 days.
Therefore (A+B) = 1/30.
Then (A+B) does the same work together for 20 days, so it is taken as 1/20 days.
Remaining work = 1/30 - 1/20 = 1/60 days.
1/60 = 60 days.
The whole work will be done by A = 60 days.
Therefore (A+B) = 1/30.
Then (A+B) does the same work together for 20 days, so it is taken as 1/20 days.
Remaining work = 1/30 - 1/20 = 1/60 days.
1/60 = 60 days.
The whole work will be done by A = 60 days.
Manmohan said:
9 years ago
Why we can take t*d?
But some problems we can take pages/time.
But some problems we can take pages/time.
Senchu Thomas said:
9 years ago
A and B can together finish a work 30 days.
They worked together for 20 days and then B left.
After another 20 days, A finished the remaining work.
ie, remaining work is 30 - 20 = 10.
10 work in 20 days.
So 1 work 2 days.
So 30 work in 30*20 = 60 days.
They worked together for 20 days and then B left.
After another 20 days, A finished the remaining work.
ie, remaining work is 30 - 20 = 10.
10 work in 20 days.
So 1 work 2 days.
So 30 work in 30*20 = 60 days.
Balaji rajendran said:
10 years ago
@Raj.
B alone can finish the work in 60 days same as A.
A+B = 1/30 and A = 1/60 then B = 1/30-1/60 = 1/60. So B alone can finish the work in 60 days.
B alone can finish the work in 60 days same as A.
A+B = 1/30 and A = 1/60 then B = 1/30-1/60 = 1/60. So B alone can finish the work in 60 days.
Balaji rajendran said:
10 years ago
@Deepak yadav.
In this problem A can finish 10 days work in 20 days so if he left alone to do a 30 days work, he will take 60 days to finish the work.
In this problem A can finish 10 days work in 20 days so if he left alone to do a 30 days work, he will take 60 days to finish the work.
Deepak yadav said:
1 decade ago
Please give its short trick.
VANI said:
1 decade ago
@Ankush.
Here in question said that 1/3 work is done by A after another 20 days. So we done 20*3.
Here in question said that 1/3 work is done by A after another 20 days. So we done 20*3.
Raj said:
1 decade ago
In how many days B alone can finish the work?
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