Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 23)
23.
A and B can do a piece of work in 30 days, while B and C can do the same work in 24 days and C and A in 20 days. They all work together for 10 days when B and C leave. How many days more will A take to finish the work?
18 days
24 days
30 days
36 days
Answer: Option
Explanation:

2(A + B + C)'s 1 day's work = ( 1 + 1 + 1 ) = 15 = 1 .
30 24 20 120 8

Therefore, (A + B + C)'s 1 day's work = 1 = 1 .
2 x 8 16

Work done by A, B, C in 10 days = 10 = 5 .
16 8

Remaining work = ( 1 - 5 ) = 3 .
8 8

A's 1 day's work = ( 1 - 1 ) = 1 .
16 24 48

Now, 1 work is done by A in 1 day.
48

So, 3 work will be done by A in ( 48 x 3 ) = 18 days.
8 8

Discussion:
61 comments Page 4 of 7.

Sanjiv said:   9 years ago
Why not like this?

x + 10/48 + 10/80 + 10/60 = 1
Then, we get x = 24 days.

Plese reply for me.

Pari said:   10 years ago
Why we take 1/24, from where its comes?

Pooja said:   10 years ago
How to add fractions like the above one in the questions? I am not getting 15/120 please explain.

Pooja said:   10 years ago
How to solve fractions like 1/30+ 1/24+1/20? Please someone explain in details I am not getting 15/120 as answer please.

Sajal said:   10 years ago
I want to ask that why we have solved the equations at the top?

Bikash Choudhury said:   1 decade ago
LCM of 30, 24, 20 is 120.

A+B B+C C+A A+B+C.

4 5 6 2 (a+b+c) = 15.

=> a+b+c = 15/2.

A+B+C do for 10 means they work together 10*15/2 = 75 units of work.

Work remains 120-75 = 45 unit.

A 's one day work = (A+B+C)-(B+C) = 15/2-5 = 5/2.

Hence A can finish the remaining work = 45*2/5 = 18.
(3)

Sikandar said:   1 decade ago
As 1 day work = (A+B+C)-(B+C).

= 1/16-1/24 = 1/48.
(1)

Varsha said:   1 decade ago
How did you calculated A's work for 1 day when we do not know any individual work for 1 day?

Hanumant said:   1 decade ago
I am not understanding how to calculate 1/48.7/240.1/80?

Shail said:   1 decade ago
@Aditya.

Because a+b.
b+c.
c+a.

So we take out common 2 in the beginning. Got it dear.


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